direction of motion 400 m The standing 400 m time of a car was 10.0 s. Question 95 (2000 Question 1) Calculate the acceleration of the car, assuming constant acceleration for the entire joumey. Question 96 (2000 Question 2) Assuming constant acceleration, calculate the speed of the car at the end of 400 m. The test on the car was repeated in the opposite direction and the standing 400 m time was 18.0 s. drection of motion 400 m The momentum of the car at the end of the first 400 m may be represented in magnitude and direction by the vector shown below. Question 97 (2000 Question 3) Which one of the vectors (A-G) best represents the momentum change of the car. between the end of the first and the end of the second run? C. D. E. G. Zero

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