What is the ∆G° and equilibrium constant at 298 K for the following reaction? 2Cl2(g) + SO2(g)  SOCl2(g) + Cl2O(g) Substance ∆H°(kJ/mol) ∆S°(J/K mol) Cl2(g) 0 223.0 SO2(g) -296.8 248.1 SOCl2(g) -212.5 309.8 Cl2O(g) 80.3 266.1

Q: For propane, the ∆H° of vaporization is 22.90 kJ/mol and the ∆S° of vaporization is 99.0 J/mol･K. At…

A: Step 1: Step 2: Step 3: Step 4:

Q: Determine ∆G° for the reaction 3 N₂(g) + 2 O₃(g) → 6 NO(g) at 223°C.   ∆H°= +257.7 kj/mol ∆S°=…

A: Gibbs Free energy (G) : The energy associated with a chemical reaction that can be used to do work.…

Q: Determine ∆G° for a reaction when ∆G = -126.1 kJ/mol and Q = 0.043 at 298 K. (R = 8.314 J/mol ･ K)

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Q: Use data in the table below to establish at 298 K for the reaction: 2 NaHCO3 (s) → Na2CO3 (s) +…

A: Here we are required to find the equilibrium constant .

Q: Calculate ∆H°, ∆S° and ∆G° at 298.15 K for the reaction H2 (g)+F2 (g)→2HF(g)

A: We know , Substance  ∆H°(kj/mol) ∆S° (j/mol K) ∆G° (kj/mol) H2(g) 0 130.58 0 F2(g) 0 202.7 0…

Q: What is ∆G0 for the reaction CN- + H2O  =  HCN + OH-? Ka for HCN = 4.0x10-10. R = 8.314 J/(mol*K)

A: "Gibbs free energy" is an estimation whether a system is able to do work or not. It is the energy…

Q: Define spontaneity of a reaction in terms of ∆G. Determine if a process is spontaneous based on…

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Q: At 1120 K, ∆G° = 67.3 kJ/mol for the reaction 3 A (g) + B (g) →2 C (g). If the partial pressures of…

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Q: Consider the reaction 3 CH41g2 ¡ C3H81g2 + 2 H21g2. Calculate ∆G at 298 K if the reaction mixture…

A: Our reaction is: 3CH4 (g)     ----->    C3H8 (g) + 2H2 (g)

Q: Consider the following reaction: 2 H2(g) + 2 NO(g) N2(g) + 2 H20(g) and the following table of…

A: • Since, here we have to calculate the standard entropy change for the given reaction. • The…

Q: Thermodynamics Quantities for Selected Substances at 298.15 K (25⁰C) Substance ∆H⁰f…

A: The degree of randomness in a system is measured in terms of entropy. The higher the entropy greater…

Q: Calculate the ∆G⁰reax value for the following reaction at 298K.CO (g) + ½ O2 (g) ↔ CO2 (g) Assuming…

A: Given, Temperature is 500 K We have to find the value of ∆G⁰reax. We will use the formula ∆G⁰reax =…

Q: At what temperature, in °C, is a certain reaction at equilibrium if ∆H = +84.2 kJ/mol and ∆S =…

A: ∆G = ∆H - T∆S Where , ∆G = Change in Gibbs free energy ∆H = Change in Enthalpy ∆S Change in Entropy…

Q: Classify the following hydrocarbons as alkanes, cycloalkane, alkene, cycloalkenes, alkyne,…

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Q: Why not? What factors relate to rate of reaction? Considering entropy as related to the number of…

A: The measure of the amount of energy that is usable in a system is known as the Gibbs free energy (G)…

Q: For propane, the ∆H° of vaporization is 22.9 kJ/mol and the ∆S° of vaporization is 99.0 J/mol･K. At…

A: Given :-  ∆H° of vaporization = 22.9 kJ/mol  ∆S° of vaporization = 99.0 J/mol.K  T = 214.5 K  To be…

Q: Consider the following reaction at 25 °C: 3 NiO(s) + 2 NH₃(g) → 3 Ni(s) + N₂(g) + 3 H₂O(g) If ∆G°…

A: The amount of energy related to a chemical reaction which can be used to extract some useful work is…

Q: For propane, the ∆H° of vaporization is 22.9 kJ/mol and the ∆S° of vaporization is 99.0 J/mol･K. At…

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Q: For benzene, the ∆H° of vaporization is 30.72 kJ/mol and the ∆S° of vaporization is 86.97 J/mol･K.…

A: Given: The ∆H° of vaporization for benzene = 30.72 kJ/mol  The ∆S° of vaporization = 86.97 J/mol･K…

Q: ne the value of AG at 298 K for the reaction,

A: From the given, COCl2 (g) ---> CO(g) + Cl2(g)    □Hrxn = [Total enthalpy of products]- [Total…

Q: For the following reaction 2NO₂(g) ⇌ N₂O₄(g) ∆H° = -58.02 kJ/mol and ∆S° = -176.6 J/mol･K. What is…

A: The reaction is –                    2NO2g ⇔N2O4g Pressure        0.2                0.2Qp…

Q: For benzene, the ∆H° of vaporization is 30.72 kJ/mol and the ∆S° of vaporization is 86.97 J/mol･K.…

A: Step 1: Step 2: Step 3: Step 4:

Q: What is ∆G° for the reaction I₂(g) → 2 I(g) at 25.0 °C if K = 6.1 x 10⁻²²? (R = 8.314 J/mol･K)

A: We are authorised to solve only one question at a time. Please post rest of the questions…

Q: What is T if Keq = 2x104? Suppose that ∆G°= -50kJ/mol, ∆H° = -80kJ/mol, ∆S° = -150J/mol K at 298 K.…

A: The details solution for this is provided below in attach image.

Q: An example of a reaction where ∆G = 0 is H2O(s)→H2O(l) @SATP any reaction that is over…

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Q: For propane, the ∆H° of vaporization is 22.90 kJ/mol and the ∆S° of vaporization is 99.0 J/mol･K. At…

A: Given: ∆H° is 22.90 kJ or 22900 J ∆S° is 99 J/mol. K Temperature is 208.5 K To find: ∆G° of…

Q: What is ∆G° for the reaction 3 O₂(g) → 2 O₃(g) at 25°C if K = 6.1 x 10⁻⁵⁸? (R = 8.314. J/mol ･ K)

A: Relation between ∆G0 and Equilibrium Constant a K is  ∆G0=-RTlnK where ∆G0 is Gibbs free energy  Ris…

Q: Calculate ∆G for the reaction given below if the partial pressure of NO2 is 0.212 atm and the…

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Q: For butane, the ∆H° of vaporization is 22.4 kJ/mol and the ∆S° of vaporization is 82.3 J/mol･K. At…

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Q: For the equilibrium A + B ⇌ C + D K was measured to be 1.51 × 10⁻² at 25°C and 55.0 at 600°C. What…

A: The entropy change is said to be the process that is used to determine the disorder or randomness of…

Q: Calculate ∆G° for the reaction of MCO3 ---> MO + CO2 at 25°C for the alkaline earth compounds Mg and…

A: The objective of the question is to determine the standard Gibbs free energy for the alkaline earth…

Q: For butane, the ∆H° of vaporization is 22.4 kJ/mol and the ∆S° of vaporization is 82.3 J/mol･K. At…

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Q: What is ∆G° for the reaction Br₂(g) → 2 Br(g) at 25.0 °C if K = 4.6 x 10⁻²⁹? (R = 8.314 J/mol･K) in…

A: Given reaction: Br₂(g) → 2 Br(g) K = 4.6 x 10⁻²⁹ We have to calculate ∆G° for the reaction.

Q: A reaction has a ∆Horx = −70 kJmol and an equilibrium constant K =2.4 × 102 at 500 K. What is ∆Sorx…

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Q: For the reaction A (g) → 3 B (g), Kp = 38700 at 298 K. When ∆G = -14.2 kJ/mol, what is the partial…

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Q: What is K for a reaction if ∆G° =-171.1 kJ/mol at 25°C? (R = 8.314 J/mol ･ K)

A: Gibbs' free energy and equilibrium constant has the following relation ∆G0 =-RT lnKeqm Or, Keqm =…

Q: The equilibrium constant for a chemical reaction is Kc = 243 at 25°C. What is the standard free…

A: Given : Equilibrium constant, K = 243 And temperature = 25 oC

Q: For propane, the ∆H° of vaporization is 22.9 kJ/mol and the ∆S° of vaporization is 99.0 J/mol･K. At…

A: We know that, ∆G° = ∆H° - T∆S° And  ∆H° = 22.9 kJ/mol ∆S° = 99.0 J/mol T = 206.0 K

Q: At what temperature, in °C, is a certain reaction at equilibrium if ∆H = +81.8 kJ/mol and ∆S =…

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