Determine the ∆G for 2N2H4(g) + 2NO2(g)  3N2(g) + 4H2O(g)at 25℃, if the initial partial pressures for N2H4, NO2, N2, and H2O are 5.0 x 10-2 atm, 5.0 x 10-2 atm, 0.50 atm, and 0.30 atm. Substance ∆G°(kJ/mol) N2H4(g) 159.4 NO2(g) 51.8 H2O(g) -228.6

Q: For the reaction A (g) → 3 B (g), Kp = 0.411 at 298 K. What is the value of ∆G for this reaction at…

A: Ans is -12.41kj/mol

Q: Industrially, methanol is synthesized using the reaction CO(g) + 2 H2(g) ↔ CH3OH(g) Calculate the…

A: Here we are required to find the equilibrium constant at 298k.

Q: Consider this reaction at 298 K: CO2 (g) + H2 (g) ⇌ CO (g) + H2O (g) Calculate ΔGrxn under the…

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Q: What is the equilibrium constant, K, for a reaction if ∆G° = -51.2 kJ/mol at 25.0 °C? (R = 8.314…

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Q: Consider the system   4NH3(g) + 3O2(g)     2N2(g) + 6H2O(l)           ∆H= -1530.4 kJ   How will…

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Q: For the gas-phase equilibrium A(g) + 2 B(g) ⇌ C(g) the initial partial pressures of A, B, and C are…

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Q: The reaction A(g) ∆ B(g) has an equilibrium constant of5.8 and under certain conditions has Q = 336.…

A: Given that : Equilibrium constant Kc = 5.8. It means that ∆G° < 1. Hence, ∆G° is negative.

Q: What is ∆G° for the reaction CaO(s) + CO₂(g) → CaCO₃(s)?

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Q: For a certain reaction at 15°C, ∆H = −10.5 kJ/mol and ∆S = 30. J/mol•K. Calculate ∆G for the…

A: ∆G is the change in gibbs free energy. The value of ∆G is given by following expression :  ∆G = ∆H -…

Q: Define spontaneity of a reaction in terms of ∆G. Determine if a process is spontaneous based on…

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Q: CaCO3(s) → CaO(s)+CO2(g)CaCO3(s) → CaO(s)+CO2(g)      Calculate the value of the equilibrium…

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Q: The discovery of the Haber process for the production of ammonia from nitrogen was a turning point…

A: First, we need to calculate the standard Gibbs free energy change (∆G°) for the reaction. The ∆G°…

Q: At 1275 K, ∆G° = 18.1 kJ/mol for the reaction 3 A (g) + B (g) → 2 C (g). If the partial pressures of…

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Q: Determine ∆G° for the reaction 2 NO₂(g) ⇌ N₂O₄(g) if K= 6.94 at 25.0 °C. (R = 8.314 J/mol･K)

A: Relation of gibbs free energy with equilibrium constant is given as:  ∆G = ∆Go + RTlnK  At…

Q: Determine ∆G° for a reaction when ∆G = -163.8 kJ/mol and Q = 0.043 at 298 K. (R = 8.314 J/mol ･ K)

A: The standard Gibb's free energy change and reaction quotient have the following relationship. ΔG =…

Q: Find Kp°  and ∆G°  for O2 (g) ↔ 2O (g), assume ideal gases If 0.150 mol of O2 (g) is placed in an…

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Q: Determine ∆G° for a reaction when ∆G = -181.2 kJ/mol and Q = 0.043 at 298 K. (R = 8.314 J/mol ･ K)

A: Please find the attachment

Q: For the reaction 2 A (g) → B (g), Kp = 0.00271 at 298 K. When ∆G = 8.35 kJ/mol, what is the partial…

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Q: Calculate the equilibrium constant at 250.0 °C.

A: Given data :

Q: What is ΔH° for the following phase change? NaCl(s) → NaCl(l) Substance ΔH°f (kJ/mol) NaCl(s)…

A: Given NaCl(s) → NaCl(l)Substance          ΔH°f (kJ/mol)NaCl(s)               –411.12NaCl(l)…

Q: At 25 °C, the thermodynamic equilibrium constant of the reaction 3C2H2(g) ⇋ C6H6(l) is K = 1.00 ×…

A: Here the given reaction is in equilibrium, For which the values are given as: Equilibrium constant…

Q: The equilibrium constant for the reaction Na2(g) → 2Na(g) is 2.47 at 1000. K. Calculate the value of…

A: Equilibrium is the state at which the rate of forward and backward reaction are equal in a…

Q: Find the the ∆H°rxn if ∆G°rxn is 420 kJ/mol and ∆S°rxn is -143 J/mol*k *refer to the photo attaced.

A: Since there are multiple questions, we are authorized to answer only the first one, that is, no. 1.…

Q: Calculate the ∆G in kJ/mol for a reaction at room temperature (~25.00°C) that has a Keq = 1000.0.…

A: We have to calculate the ∆G.

Q: The vaporization of methanol CH₃OH(l) ⇌ CH₃OH(g) is an endothermic process in which ∆Hvap = 37.4…

A: ∆Hvap = 37.4KJ/mol ∆Svap = 111 J mol-1K-1  Boiling Point at 605 torr =? 605 torr = 0.796053 atm  R =…

Q: Oxygen (O₂) is necessary for cellular respiration; it must be transported from the lungs to tissues…

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Q: Determine the temperature of a reaction if K = 1.20 x 10⁻⁶ when ∆G° = +19.30 kJ/mol.

A: This reaction must be in equilibrium. apply the formula at equilibrium, ∆G0 = - R T lnk

Q: Determine the ΔS0rxn of the reaction below:    N2H4(l) + N2O4(g) → N2(g) + H2O(g) ΔS0f (J/K)…

A: Ans

Q: At 1125 K, ∆G° = 28.4 kJ/mol for the reaction 3 A (g) + B (g) → 2 C (g). If the partial pressures of…

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Q: For the reaction A (g) → 3 B (g), Kp = 72300 at 298 K. When ∆G = -14.2 kJ/mol, what is the partial…

A: A(g)3B(g)Kp = 72300 at 298 K. ∆G = -14.2 kJ/molpartial pressure of B = 2.00 atmTemperature…

Q: Determine the temperature of a reaction if K = 1.2 x 10⁻⁶ when ∆G° = +19.9 kJ/mol

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Q: Consider the following reaction at 25 °C: Ba(OH)₂･8 H₂O(s) + 2 NH₄Cl(s) → BaCl₂(s) + 2 NH₃(g) + 10…

A: Ba(OH)₂.8 H₂O(s) + 2 NH₄Cl(s) → BaCl₂(s) + 2 NH₃(g) + 10 H₂O(l) ∆G° = -14.1 kJ/mol The pressure of…

Q: The discovery of the Haber process for the production of ammonia from nitrogen was a turning point…

A: Approach to solving the question: Detailed explanation: Examples: Key references:

Q: Using data listed in Table 1 below, calculate the equilibrium constant (K) for the following…

A: The given reaction is the dissociation of the liquid water molecule into gaseous hydrogen and…

Q: Consider the following equilibrium: N2O41g2 ∆ 2 NO21g2Thermodynamic data on these gases are given in…

A: Given: The reaction given is, N2O4(g)→2NO2(g) For the given reaction, the temperature at equilibrium…

Q: What is K for a reaction if ∆G° =173.2 kJ/mol at 25.0 °C? (R = 8.314 J/mol ･ K)

A: Given, Standard gibbs free energy (∆G°) = 173.2 kJ/mol = 173.2 × 1000 J/mol = 173200 J/mol…

Q: For the reaction 2 A (g) → B (g), Kp = 0.00347 at 298 K. When ∆G = 8.35 kJ/mol, what is the partial…

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Q: At 1125 K, ∆G° = 43.2 kJ/mol for the reaction 3 A (g) + B (g) → 2 C (g). If the partial pressures of…

A: We have to calculate free energy for the reaction  3 A (g) + B (g) → 2 C (g)

Q: For the equilibrium A + B ⇌ C + D K was measured to be 1.51 × 10⁻² at 25°C and 55.0 at 600°C. What…

A: The entropy change is said to be the process that is used to determine the disorder or randomness of…

Q: Determine ∆G° for a reaction when ∆G = -138.2 kJ/mol and Q = 0.043 at 298 K. (R = 8.314 J/mol ･ K)

A: ∆G° for a reaction has to be determined

Q: What is ∆G° for the reaction Br₂(g) → 2 Br(g) at 25.0 °C if K = 4.6 x 10⁻²⁹? (R = 8.314 J/mol･K) in…

A: Given reaction: Br₂(g) → 2 Br(g) K = 4.6 x 10⁻²⁹ We have to calculate ∆G° for the reaction.

Q: Determine the temperature of a reaction if K = 1.20 x 10⁻⁶ when ∆G° = +30.40 kJ/mol.

A: We have been given ∆G° = +30.40 kJ/mol and K = 1.20 x 10⁻⁶.We have been asked to calculate the…

Q: At 425 K, ∆G = -24.3 kJ/mol for the reaction 2 A (g) → B (g). If the partial pressures of A and B…

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Q: At 460 K, ∆G = -11.2 kJ/mol for the reaction 2 A (g) → B (g). If the partial pressures of A and B…

A: For the reaction 2A --> B As in the question, it is not mentioned that whether the reaction is in…