For the equilibrium A + B ⇌ C + D K was measured to be 1.51 × 10⁻² at 25°C and 55.0 at 600°C. What is ∆S° for the reaction? Assume ∆H° and ∆S° are temperature independent.

Q: Determine ∆G° for the reaction 3 N₂(g) + 2 O₃(g) → 6 NO(g) at 223°C.   ∆H°= +257.7 kj/mol ∆S°=…

A: Gibbs Free energy (G) : The energy associated with a chemical reaction that can be used to do work.…

Q: For a certain reaction at 15°C, ∆H = −10.5 kJ/mol and ∆S = 30. J/mol•K. Calculate ∆G for the…

A: ∆G is the change in gibbs free energy. The value of ∆G is given by following expression :  ∆G = ∆H -…

Q: Define spontaneity of a reaction in terms of ∆G. Determine if a process is spontaneous based on…

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Q: Consider the reaction, HQ ⇌ H⁺(aq) + Q⁻(aq). At 298 K, the ∆S°rxn = -81.0 J/mol･K and the ∆G°rxn of…

A: The ∆H°rxn of the given reaction can bu calculated using following thermodynamics relation: ∆H°rxn =…

Q: Consider the reaction 3 CH41g2 ¡ C3H81g2 + 2 H21g2. Calculate ∆G at 298 K if the reaction mixture…

A: Our reaction is: 3CH4 (g)     ----->    C3H8 (g) + 2H2 (g)

Q: How can we calculate an Equilibrium Constant from ∆G?

A: ∆G is Gibbs free energy change ∆G= - RT logn K under standard conditions ∆G0=-2.303 RT log10 K  or…

Q: Calculate the ∆G⁰reax value for the following reaction at 298K.CO (g) + ½ O2 (g) ↔ CO2 (g) Assuming…

A: Given, Temperature is 500 K We have to find the value of ∆G⁰reax. We will use the formula ∆G⁰reax =…

Q: Determine ∆G° for the reaction 2 NO₂(g) ⇌ N₂O₄(g) if K= 6.94 at 25.0 °C. (R = 8.314 J/mol･K)

A: Relation of gibbs free energy with equilibrium constant is given as:  ∆G = ∆Go + RTlnK  At…

Q: For the reaction A (g) → 3 B (g), Kp = 51300 at 298 K. When ∆G = -14.2 kJ/mol, what is the partial…

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Q: Calculate the ∆G⁰reax value for the following reaction running at 298K. CO (g) + ½ O2 (g) ↔ CO2 (g)…

A: The given chemical equation as follows --- CO (g)   +    ½ O2 (g)    ↔    CO2 (g)…

Q: Calculate the free-energy change for the synthesis of ammonia at 25°C given the following sets of…

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Q: Calculate the value of ∆G⁰reak for the following reaction walking at 298K CO(g) + ½ O2(g) ↔ CO2(g)…

A: Given that - CO(g) + ½ O2(g) ↔ CO2(g)   Now - G°(CO) = -137.16 kJ/mol G°(O2) = 0.0 kJ/mol G°(CO2) =…

Q: When the reaction FeO (s) + CO (g) ↔ Fe (s) + CO2 (g) takes place at 600 K, , it is observed that a)…

A: a).  = equilibrium constant at 600°C =  0.900

Q: Consider the following reaction at 25 °C: 3 NiO(s) + 2 NH₃(g) → 3 Ni(s) + N₂(g) + 3 H₂O(g) If ∆G°…

A: The amount of energy related to a chemical reaction which can be used to extract some useful work is…

Q: Determine the temperature of a reaction if K = 1.20 x 10⁻⁶ when ∆G° = +35.60 kJ/mol.

A: Given change in Gibbs free energy is +35.60 kJ/mol.

Q: For the following reaction 2NO₂(g) ⇌ N₂O₄(g) ∆H° = -58.02 kJ/mol and ∆S° = -176.6 J/mol･K. What is…

A: The reaction is –                    2NO2g ⇔N2O4g Pressure        0.2                0.2Qp…

Q: At 1275 K, ∆G° = 41.1 kJ/mol for the reaction 3 A (g) + B (g) → 2 C (g). If the partial pressures of…

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Q: For the reaction A (g) → 3 B (g), Kp = 35900 at 298 K. When ∆G = -14.2 kJ/mol, what is the partial…

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Q: Calculate the ∆G in kJ/mol for a reaction at room temperature (~25.00°C) that has a Keq = 1000.0.…

A: We have to calculate the ∆G.

Q: At 1125 K, ∆G° = 28.4 kJ/mol for the reaction 3 A (g) + B (g) → 2 C (g). If the partial pressures of…

A:

Q: Consider the following reaction at 25 °C: Ba(OH)₂･8 H₂O(s) + 2 NH₄Cl(s) → BaCl₂(s) + 2 NH₃(g) + 10…

A: Ba(OH)₂.8 H₂O(s) + 2 NH₄Cl(s) → BaCl₂(s) + 2 NH₃(g) + 10 H₂O(l) ∆G° = -14.1 kJ/mol The pressure of…

Q: The dissolution of CaCl2 in water is product-favored, but the temperature of the surrounding water…

A: Change in entropy of mixing of gases (∆S)- Entropy of mixing of gases is always positive Because…

Q: Determine the temperature of a reaction if K = 1.20 x 10⁻⁶ when ∆G° = +37.60 kJ/mol.

A: Formula used :-  ∆G° = -2.303RTlogk   ∆G° = change in Gibb's free energy  k = equilibrium constant…

Q: Calculate the ∆G⁰reac value for the following reaction walking at 298 Kelvin. CO (g) + ½ O2 (g) ↔…

A: Given that, The required chemical reaction as follows --- CO (g)    +    ½ O2 (g)    ↔    CO2 (g)…

Q: Determine the temperature of a reaction if K = 1.20 x 10⁻⁶ when ∆G° = +20.70 kJ/mol

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Q: At 1125 K, ∆G° = 43.2 kJ/mol for the reaction 3 A (g) + B (g) → 2 C (g). If the partial pressures of…

A: We have to calculate free energy for the reaction  3 A (g) + B (g) → 2 C (g)

Q: What is ∆G° for the reaction Br₂(g) → 2 Br(g) at 25.0 °C if K = 4.6 x 10⁻²⁹? (R = 8.314 J/mol･K) in…

A: Given reaction: Br₂(g) → 2 Br(g) K = 4.6 x 10⁻²⁹ We have to calculate ∆G° for the reaction.

Q: A reaction has a ∆Horx = −70 kJmol and an equilibrium constant K =2.4 × 102 at 500 K. What is ∆Sorx…

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Q: For the reaction A (g) → 3 B (g), Kp = 43300 at 298 K. When ∆G = -14.2 kJ/mol, what is the partial…

A: Given:Partial pressure of A, PA=  ?Partial pressure of B, PB= 2.0 atm∆G = -14.2 kJ/mol Kp =…

Q: For the reaction A (g) → 3 B (g), Kp = 38700 at 298 K. When ∆G = -14.2 kJ/mol, what is the partial…

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Q: For the following reaction H₂(g) + I₂(g) ⇌ 2HI(g) ∆H° = -10.64 kJ/mol and ∆S° = 21.48 J/mol･K. What…

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Q: At

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Q: For the reaction A (g) → 3 B (g), Kp = 0.767 at 298 K. What is the value of ∆G for this reaction at…

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Q: Consider the following reaction: CO2(g)+CCl4(g)⇌2COCl2(g)CO2(�)+CCl4(�)⇌2COCl2(�). Calculate…

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Q: Determine the temperature of a reaction if K = 1.20 x 10⁻⁶ when ∆G° = +30.40 kJ/mol.

A: We have been given ∆G° = +30.40 kJ/mol and K = 1.20 x 10⁻⁶.We have been asked to calculate the…

Q: Is the standard free-energy change, ∆G°, always larger than ∆G?

A: solution;   ∆Go not always larger than ∆G,

Q: The ∆H° for a reaction is -46.8 kJ mol⁻¹ and ∆S° is -0.152 kJ mol⁻¹ K⁻¹. Calculate the ∆G° for this…

A: ∆H° = -46.8 kJ mol⁻¹∆S° = -0.152 kJ mol⁻¹ K⁻¹T = 298 K∆G° = ?Note: Relationship between enthalpy…

Q: The following vapor pressures of water have been measured for the reaction: Calculate Kp, ∆G0, ∆H0…

A: