What is the curent read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. Input R1, R2, and R3 for resistors R1, R2, and R3 respectively. Input E for the emf E, Use context clues to figure out if you need to input a numerical value, variable, word, etc. AN numerical answers should be in three significant figures. R| R2 R3 First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: Plugging in values, the current across the resistor R1 is equal to: (Piease note that the curent is in miliamperes) mA Similarly the current across R2 is: 12 = mA And the current across R3 is: 13 = mA The current read by the ammeter is the sum of the ourrents across each resistor: |=l1 +12+l3 Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors in parallel is: 1/Req =/R1 + 1/R2 +1/ Thus. Reg=

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
What is the current read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts.
Input R1, R2, and R3 for resistors R1. R2, and R3 respectively. Input E for the emf E. Use context clues to figure out if you need to input a numerical value, variable, word, etc. All numerical answers should be in three significant figures.
R|
R2
R3
First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current:
Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is
milliamperes)
Similarly the current across R2 is:
12=
mA
And the current across R3 is:
13 =
mA
The current read by the ammeter is the sum of the currents across each resistor:
1=h+/2 +13
|=
Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law.
The equivalent resistance of the three resistors in parallel is:
1/Re =1/R, +1/R2 +1/
Thus,
Reg=
Transcribed Image Text:What is the current read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. Input R1, R2, and R3 for resistors R1. R2, and R3 respectively. Input E for the emf E. Use context clues to figure out if you need to input a numerical value, variable, word, etc. All numerical answers should be in three significant figures. R| R2 R3 First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is milliamperes) Similarly the current across R2 is: 12= mA And the current across R3 is: 13 = mA The current read by the ammeter is the sum of the currents across each resistor: 1=h+/2 +13 |= Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors in parallel is: 1/Re =1/R, +1/R2 +1/ Thus, Reg=
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Combination of resistance
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON