In the circuit shown in the figure (Figure 1), the 6.0 2 resistor is consuming energy at a rate of 18 J/s when the current through it flows as shown. Find the current through the ammeter A. Express your answer with the appropriate units. HA ? I = Value Units Submit Request Answer Part B gure 1 of 1> What are the polarity and emf of the battery E, assuming it has negligible internal resistance? Express your answer with the appropriate units. Enter positive value if the polarity of the battery is the same as shown in the figure and negative value in another case. 20.0 1 170 HA E = ? S6.00 S190 20.0 0 E = - 45.8 V 25 V S3.00 Submit Previous Answers Request Answer ww L00 130

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Part A
In the circuit shown in the figure (Figure 1), the 6.0 2
resistor is consuming energy at a rate of 18 J/s when
the current through it flows as shown.
Find the current through the ammeter A.
Express your answer with the appropriate units.
HA
I = Value
Units
Submit
Request Answer
Part B
Figure
1 of 1>
What are the polarity and emf of the battery E, assuming it has negligible internal resistance?
Express your answer with the appropriate units. Enter positive value if the polarity of the battery is the same
as shown in the figure and negative value in another case.
20.0 2
170
ol
HA
?
ww
E = ?-
36.00
20.0 0
S190
E = - 45.8
V
25 V
3.00
Submit
Previous Answers Request Answer
130
1.00
X Incorrect; Try Again; 9 attempts remaining
Transcribed Image Text:Part A In the circuit shown in the figure (Figure 1), the 6.0 2 resistor is consuming energy at a rate of 18 J/s when the current through it flows as shown. Find the current through the ammeter A. Express your answer with the appropriate units. HA I = Value Units Submit Request Answer Part B Figure 1 of 1> What are the polarity and emf of the battery E, assuming it has negligible internal resistance? Express your answer with the appropriate units. Enter positive value if the polarity of the battery is the same as shown in the figure and negative value in another case. 20.0 2 170 ol HA ? ww E = ?- 36.00 20.0 0 S190 E = - 45.8 V 25 V 3.00 Submit Previous Answers Request Answer 130 1.00 X Incorrect; Try Again; 9 attempts remaining
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