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What is the change of energy (L. atm) of a system that absorbed 16.5 L.atm of heat and had its volume changed from 5.2 L to 10.9 L against a pressure of 1.5 atm? O AE = 16.5 + [1.5(10.9 + 5.2)] O AE = -16.5 + [1.5(10.9 - 5.2)] AE = -16.5 + [-1.5(10.9 - 5.2)] O AE = 16.5 +[- 1.5(10.9 - 5.2)]

What is the change of energy (L. atm) of a system that absorbed 16.5 L.atm of heat and had its volume changed from 5.2 L to 10.9 L against a pressure of 1.5 atm? O AE = 16.5 + [1.5(10.9 + 5.2)] O AE = -16.5 + [1.5(10.9 - 5.2)] AE = -16.5 + [-1.5(10.9 - 5.2)] O AE = 16.5 +[- 1.5(10.9 - 5.2)]

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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What is the change of energy (L. atm) of a system that absorbed 16.5 L.atm of heat and had its volume changed from 5.2 L to 10.9 L against a pressure of 1.5 atm? O AE = 16.5 + [1.5(10.9 + 5.2)] O AE = -16.5 + [1.5(10.9 - 5.2)] AE = -16.5 + [-1.5(10.9 - 5.2)] AE = 16.5 +[- 1.5(10.9 - 5.2)]
Transcribed Image Text:What is the change of energy (L. atm) of a system that absorbed 16.5 L.atm of heat and had its volume changed from 5.2 L to 10.9 L against a pressure of 1.5 atm? O AE = 16.5 + [1.5(10.9 + 5.2)] O AE = -16.5 + [1.5(10.9 - 5.2)] AE = -16.5 + [-1.5(10.9 - 5.2)] AE = 16.5 +[- 1.5(10.9 - 5.2)]
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