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· A sealed piston cylinder with an initial temperature of 0 °C holds 200 kg of R -134a at 400 kPa. If the pressure inside the piston remains constant and the R-134a is heated until it occupies a final volume of 0.50 m³, determine the change in internal energy for the R– 134a. |

· A sealed piston cylinder with an initial temperature of 0 °C holds 200 kg of R -134a at 400 kPa. If the pressure inside the piston remains constant and the R-134a is heated until it occupies a final volume of 0.50 m³, determine the change in internal energy for the R– 134a. |

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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### Thermodynamics: Problem 3.ADD1 **Problem Statement:** A sealed piston cylinder with an initial temperature of 0°C holds 200 kg of R-134a at 400 kPa. If the pressure inside the piston remains constant and the R-134a is heated until it occupies a final volume of 0.50 m³, determine the change in internal energy for the R-134a. ### Key Concepts: 1. **Piston Cylinder Device:** A piston cylinder is a common device used in thermodynamics to study the behavior of gases and liquids under varying conditions of pressure and temperature. 2. **Initial and Final States:** - **Initial State:** - Temperature = 0°C - Mass = 200 kg - Pressure = 400 kPa - **Final State:** - Volume = 0.50 m³ - Pressure (Constant) = 400 kPa - Temperature (To Be Determined) 3. **Properties of R-134a:** R-134a is a refrigerant commonly used in thermodynamic applications. The properties of R-134a at various temperatures and pressures can be found in standard thermodynamic tables. 4. **Steps to Solve the Problem:** - **Step 1:** Use thermodynamic tables to find properties of R-134a at the initial state (0°C, 400 kPa). - **Step 2:** Heat the refrigerant and determine the properties of the gas at the final state (400 kPa, Volume = 0.5 m³). - **Step 3:** Calculate the change in internal energy (ΔU) by finding the difference in internal energy between the final state and the initial state. ### Graphs and Diagrams: This problem may involve using the Pressure-Volume (P-V) and Temperature-Entropy (T-s) diagrams to understand the process. However, specific graphs and diagrams are not provided in the problem statement. ### Conclusion: By utilizing the data from thermodynamic tables and understanding the properties of R-134a, the change in internal energy can be determined effectively for the given process. This problem accentuates the importance of thermodynamic principles in practical applications.
Transcribed Image Text:### Thermodynamics: Problem 3.ADD1 **Problem Statement:** A sealed piston cylinder with an initial temperature of 0°C holds 200 kg of R-134a at 400 kPa. If the pressure inside the piston remains constant and the R-134a is heated until it occupies a final volume of 0.50 m³, determine the change in internal energy for the R-134a. ### Key Concepts: 1. **Piston Cylinder Device:** A piston cylinder is a common device used in thermodynamics to study the behavior of gases and liquids under varying conditions of pressure and temperature. 2. **Initial and Final States:** - **Initial State:** - Temperature = 0°C - Mass = 200 kg - Pressure = 400 kPa - **Final State:** - Volume = 0.50 m³ - Pressure (Constant) = 400 kPa - Temperature (To Be Determined) 3. **Properties of R-134a:** R-134a is a refrigerant commonly used in thermodynamic applications. The properties of R-134a at various temperatures and pressures can be found in standard thermodynamic tables. 4. **Steps to Solve the Problem:** - **Step 1:** Use thermodynamic tables to find properties of R-134a at the initial state (0°C, 400 kPa). - **Step 2:** Heat the refrigerant and determine the properties of the gas at the final state (400 kPa, Volume = 0.5 m³). - **Step 3:** Calculate the change in internal energy (ΔU) by finding the difference in internal energy between the final state and the initial state. ### Graphs and Diagrams: This problem may involve using the Pressure-Volume (P-V) and Temperature-Entropy (T-s) diagrams to understand the process. However, specific graphs and diagrams are not provided in the problem statement. ### Conclusion: By utilizing the data from thermodynamic tables and understanding the properties of R-134a, the change in internal energy can be determined effectively for the given process. This problem accentuates the importance of thermodynamic principles in practical applications.
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