What is the average instantaneous speed of the runner during this 16 s time interval? The graph shown is a velocity-time graph depicting the motion of an object over a period of 16 seconds. **Description of the Graph:**- **Axes:** - The horizontal axis represents time in seconds (s), marked from 0 to 16 seconds. - The vertical axis represents velocity in meters per second (m/s), ranging from -10 to 10 m/s.**Plot Details:**1. At time \( t = 0 \) seconds, the velocity is 0 m/s.2. From \( t = 0 \) to \( t = 2 \) seconds, the velocity increases linearly to 8 m/s.3. From \( t = 2 \) to \( t = 4 \) seconds, the velocity decreases linearly back to 0 m/s.4. From \( t = 4 \) to \( t = 6 \) seconds, the velocity continues to decrease linearly to -8 m/s.5. From \( t = 6 \) to \( t = 8 \) seconds, the velocity increases linearly to 5 m/s.6. From \( t = 8 \) to \( t = 12 \) seconds, the velocity decreases linearly back to 0 m/s.7. From \( t = 12 \) to \( t = 14 \) seconds, the velocity continues to decrease to -5 m/s.8. Finally, from \( t = 14 \) to \( t = 16 \) seconds, the velocity increases back to 5 m/s.**Interpretation:**- The graph illustrates changes in velocity over time, indicating alternating periods of acceleration and deceleration.- Positive velocity values indicate motion in one direction, while negative values indicate motion in the opposite direction.- The zero crossings of the velocity indicate points where the object momentarily comes to rest before changing direction.

Solution: Given that the interval of velocity and time since we know that Instantaneous speed is found by taking the absolute value of instantaneous velocity, and it is always positive. Average speed is total distance traveled divided by elapsed timeTherefore Total distance =16-30+48+0-28+80=86 m and total time elapsed =2+4+2+4+2+2=16 s so , the instantaneous speed =8616=5.375 m/s Answer