t rate over a distance of 178 m. The entire trip lasts a total duration of 18.7 s. What were the magnitudes of the car s accelerations

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A car starts from rest, then accelerates at a constant rate over a distance of 96 m. It then immediately decelerates at a constant rate over a distance of 178 m. The entire trip lasts a total duration of 18.7 s. What were the magnitudes of the car s accelerations for the speedup and slowdown stages respectively?

A car starts from rest, then accelerates at a constant rate over a distance of 96 m. It then immediately decelerates at a constant rate
over a distance of 178 m. The entire trip lasts a total duration of 18.7 s. What were the magnitudes of the car s accelerations for the
speedup and slowdown stages respectively?
4.47 m/s^2, then 2.41 m/s^2
5.13 m/s^2, then 9.52 m/s^2
1.57 m/s^2, then 1.57 m/s^2
9.52 m/s^2, then 5.13 m/s^2
Transcribed Image Text:A car starts from rest, then accelerates at a constant rate over a distance of 96 m. It then immediately decelerates at a constant rate over a distance of 178 m. The entire trip lasts a total duration of 18.7 s. What were the magnitudes of the car s accelerations for the speedup and slowdown stages respectively? 4.47 m/s^2, then 2.41 m/s^2 5.13 m/s^2, then 9.52 m/s^2 1.57 m/s^2, then 1.57 m/s^2 9.52 m/s^2, then 5.13 m/s^2
Expert Solution
Step 1

We know that a car starts from the rest and then accelerates at a constant rate over a distance of d = 96 m. 

It then immediately decelerates at a constant rate over a distance of 178 m

We know that the second equation of motion is given as

d= ut +12at2

d is the distance travel 

a  is the acceleration 

u is the initial velocity =0 

t is the time to travel a distance d 

 

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