A cyclist travels from point A to point B in 10 min. During the first 2.0 min of her trip, she maintains a uniform acceleration of 0.051 m/s2. She then travels at constant velocity for the next 5.0 min. Next, she decelerates at a constant rate so that she comes to a rest at point B 3.0 min later. (a) Sketch the velocity-versus-time graph for the trip. ELh Velocity v Velocity v Velocity v Time t Time t Time t Velocity v Time t

A cyclist travels from point A to point B in 10 min. During the first 2.0 min of her trip, she maintains a uniform acceleration of 0.051 m/s2. She then travels at constant velocity for the next 5.0 min. Next, she decelerates at a constant rate so that she comes to a rest at point B 3.0 min later. (a) Sketch the velocity-versus-time graph for the trip. ELh Velocity v Velocity v Velocity v Time t Time t Time t Velocity v Time t

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

From t = 0 to t = 4.59 min, a man stands still, and from t = 4.59 min to t = 9.18 min, he walks briskly in a straight line at a constant speed of 1.22 m/s. What are (a) his average velocity vavg and (b) his average acceleration aavg in the time interval 1.00 min to 5.59 min? What are (c) vavg and (d) aavg in the time interval 2.00 min to 6.59 min?
A car traveling 56.0 km/h is 23.0 m from a barrier when the driver slams on the brakes. The car hits the barrier 2.05 s later. a) What is the magnitude of the car's constant acceleration before impact? b) How fast is the car traveling at impact?
A jogger jogs from one end to the other of a straight track in 1.08 min and then back to the starting point in 1.53 min. What is the jogger's average speed at the following points? (Assume the track is 100 m long.) a in jogging to the far end of the track (b) coming back to the starting point (c) for the total jog
Freight trains can produce only relatively small accelerations and decelerations. a) What is the final velocity of a freight train that accelerates at a rate of 0.0418 m/s² for 6 min, starting with an initial velocity of 3.22 m/s?
A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 3.00 m/s, and her takeoff point is 1.30 m above the pool.(a) How long are her feet in the air? s(b) What is her highest point above the board? m(c) What is her velocity when her feet hit the water? m/s
A record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.55 m/s2 for 10.0 s. 2. Maintain a constant velocity for the next 1.00 min. 3. Apply a constant negative acceleration of −9.03 m/s2 for 2.82 s. (a) What was the total displacement for the trip? (b) What were the average speeds for legs 1, 2, and 3 of the trip, as well as for the complete trip?
A car starts from rest, then accelerates at a constant rate over a distance of 57 m. It then immediately decelerates at a constant rate over a distance of 113 m. The entire trip lasts a total duration of 27.5 s. What were the magnitudes of the car s accelerations for the speedup and slowdown stages respectively? The car comes to a complete stop at the end of the braking phase. a. 4.11 m/s^2, then 2.07 m/s^2 b. 1.34 m/s^2, then 0.68 m/s^2 c. 2.07 m/s^2, then 4.11 m/s^2 d. 0.45 m/s^2, then 0.45 m/s^2
QuesuvI Z VETJ Points: 2 Kim is waiting for the results of her physics exam. She walks 8.0 metres north in 5.0 seconds, then 25 metres south in 15.0 seconds, then 10.0 metres north in 10.0 seconds. Use this information to answer the following questions: (1) What is Kim's average speed? (ii) What is Kim's average velocity? DA) Kim's speed is 1.4 m/s B) Kim's speed is 0.23 m/s C) Kim's speed is -0.23 m/s D) Kim's speed is -1.4 m/s E) Kim's velocity is 1.4 m/s [N] F) Kim's velocity is 0.23 m/s [S] G) Kim's velocity is 0.23 m/s [N] ⒸH) Kim's velocity is 1 4 m/s [S] Clear selection Question 3 of 13