What is AS at 298 K for the following reaction? Fe2O3(s) + 3CO(g) - 3CO2(g) + 2Fe(s) Substance AGf(kJ/mol) AHf(kJ/mol) Fe2O3(s) CO(g) CO2(g) -741.0 -137.2 -394.4 -822.2 -110.5 -393.5
What is AS at 298 K for the following reaction? Fe2O3(s) + 3CO(g) - 3CO2(g) + 2Fe(s) Substance AGf(kJ/mol) AHf(kJ/mol) Fe2O3(s) CO(g) CO2(g) -741.0 -137.2 -394.4 -822.2 -110.5 -393.5
Chemistry
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Chapter1: Chemical Foundations
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![**Calculating ΔS° at 298 K for a Chemical Reaction**
This section explains how to determine the standard entropy change (ΔS°) at 298 K for the following chemical reaction:
\[ \text{Fe}_2\text{O}_3(s) + 3\text{CO}(g) \rightarrow 3\text{CO}_2(g) + 2\text{Fe}(s) \]
The table below provides the standard Gibbs free energy of formation (ΔG°f) and standard enthalpy of formation (ΔH°f) in kilojoules per mole (kJ/mol) for each substance involved in the reaction:
| Substance | ΔG°f (kJ/mol) | ΔH°f (kJ/mol) |
|-------------|---------------|---------------|
| Fe₂O₃(s) | -741.0 | -822.2 |
| CO(g) | -137.2 | -110.5 |
| CO₂(g) | -394.4 | -393.5 |
To calculate ΔS°, use the formula relating Gibbs free energy, enthalpy, and entropy:
\[ ΔG° = ΔH° - TΔS° \]
where \( ΔG° \) is the standard Gibbs free energy change, \( ΔH° \) is the standard enthalpy change, and \( T \) is the temperature in Kelvin.
By calculating these thermodynamic values for the entire reaction, we can determine the change in entropy (ΔS°) at the specified temperature.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faed2933e-b67f-42a0-9fac-b6dce0e828b0%2F48f9ec08-0b36-4410-bbd2-e0e40b1ae68f%2Ffi2ax23_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Calculating ΔS° at 298 K for a Chemical Reaction**
This section explains how to determine the standard entropy change (ΔS°) at 298 K for the following chemical reaction:
\[ \text{Fe}_2\text{O}_3(s) + 3\text{CO}(g) \rightarrow 3\text{CO}_2(g) + 2\text{Fe}(s) \]
The table below provides the standard Gibbs free energy of formation (ΔG°f) and standard enthalpy of formation (ΔH°f) in kilojoules per mole (kJ/mol) for each substance involved in the reaction:
| Substance | ΔG°f (kJ/mol) | ΔH°f (kJ/mol) |
|-------------|---------------|---------------|
| Fe₂O₃(s) | -741.0 | -822.2 |
| CO(g) | -137.2 | -110.5 |
| CO₂(g) | -394.4 | -393.5 |
To calculate ΔS°, use the formula relating Gibbs free energy, enthalpy, and entropy:
\[ ΔG° = ΔH° - TΔS° \]
where \( ΔG° \) is the standard Gibbs free energy change, \( ΔH° \) is the standard enthalpy change, and \( T \) is the temperature in Kelvin.
By calculating these thermodynamic values for the entire reaction, we can determine the change in entropy (ΔS°) at the specified temperature.
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