### Determining ΔS° for 2 O₃(g) ⟶ 3 O₂(g)To find the standard entropy change (ΔS°) for the given reaction, we need to use the standard entropy values (S°) of the reactants and products. The reaction is:\[ 2 \: \text{O}_3 \: (g) \: \rightarrow \: 3 \: \text{O}_2 \: (g) \]The provided table lists the standard entropy values for the substances involved:| **Substance** | **S° (J/mol·K)** ||---------------|------------------|| O₃ (g) | 239 || O₂ (g) | 205 |**Step-by-Step Solution:**1. **Write the balanced chemical equation**: \[ 2 \: \text{O}_3 \: (g) \: \rightarrow \: 3 \: \text{O}_2 \: (g) \]2. **Determine the total standard entropy of the reactants**: Since there are 2 moles of O₃ (g), \[ S_{\text{total reactants}} = 2 \times 239 \: \text{J/mol·K} = 478 \: \text{J/mol·K} \]3. **Determine the total standard entropy of the products**: Since there are 3 moles of O₂ (g), \[ S_{\text{total products}} = 3 \times 205 \: \text{J/mol·K} = 615 \: \text{J/mol·K} \]4. **Calculate the standard entropy change (ΔS°)**: \[ \Delta S^\circ = \sum S^\circ_{\text{products}} - \sum S^\circ_{\text{reactants}} \] \[ \Delta S^\circ = 615 \: \text{J/mol·K} - 478 \: \text{J/mol·K} \] \[ \Delta S^\circ = 137 \: \text{J/mol·K} \]**Conclusion:**The standard entropy change (ΔS°) for the reaction \( \text{2 O}_3 (g) \: \rightarrow \: \

Given: So(O3g)=239 J/mol·KSo(O2g)=205 J/mol·K

Answered: Determine AS° for 2 03(g) → 3 O₂(g).…

Science

Chemistry

Determine AS° for 2 03(g) → 3 O₂(g). Substance S° (J/mol.K) 03 (9) 239 205 O2 (g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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