Use the free energies of formation given below to calculate the equilibrium constant (Keg) for the following reaction at 298 K.2 A2X (g)3 Z2 (g)2 XZ2 (g) +2 A2Z (g)Keg = ?(The letters shown are theoretical elements)Using the following Data:A2X (g)Z2 (g)XZ2 (g)A2Z (g)AG°f(kJ/mol)-33.40.00-300.1-228.6О 1490.670no right answerO 2,57 1034.39 -10173 19 Thermodynamic Quantities for Selected Substances at 298.15 K (25°C)AHfAGfAS°AHf(kJ/mol)AGf(kJ/mol)AS°Substance(kJ/mol)(kJ/mol)(J/mol-K)Substance(J/mol-K)AluminumChlorineCI (g)C (аq)Cl2 (g)HCI (aq)HCI (g)ChromiumAl (s)AIC13 (s)28.32121.7105,7- 131,2165.2- 705.6- 630.0109.3- 167.256.5Al203 (s)- 1669.81576.551.00222,96- 131.2-95.27- 167.256.5186,69Barium--Ba(s)BaCO3(s)BaO(s)BerylliumBe(s)63.2-92.30- 1216,3- 553.5- 1137.6112.1Cr (g)Cr (s)Cr203 (s)CobaltСо (g)CopperCu (s)CuCl2 (s)CuO (s)- 525.170.42397.5352.6174.223.69.44- 1139.7- 1058.181.2BeO(s)Be(ОН)2(8)13.7750.21- 608.4-579,1- 817.9- 905.8439393179Bromine111.8- 120.9Br(g)Br-(aq)Br2(g)Br2(1)HBr(g)CalciumCa(g)Ca(s)CaCO3 (s, calcite)CaCl2(s)CaF2(s)CaO(s)Ca(OH)2(s)CaSO4(s)82.38174.933.30108.1- 102.8- 167,7- 128,3- 147.980.71- 205.930,713.14245.3- 156,142,59-Cu20 (s)FluorineF (g)F- (aq)F2 (g)HF (g)Hydrogen152.3- 170.792.36-36.23-53.22198.4980.061.9158.7- 13.8202,7179.3145,5154.841.4- 332.6- 278,8- 1207.1- 795.8-1128.7692.88- 268.61-270.70173.51- 7484104.6- 1219,6- 1167.368.87H (g)217.94203.26114.60- 635.5- 986.2-604.17- 898.539.7583.4H+(aq)H+ (g)Н2 (g)IodineI (g)I (aq)I2 (g)I2 (s)НI (g)1536.21517.0108.9- 1434.0- 1321.8106.7130.58Carbon718.4C(g)C(s, diamond)C(s, graphite)CCI4 (g)CCI4 (1)672.9158.0106.6070.16180,661.882.842.43-55.19-51.57111.35.6962.2519.37260,57- 106.7- 139.3-64.0309.4116.73- 68.6214.425.941.30206.3- 679.9- 74,8CF4 (g)CH4 (g)C2H2 (g)C2H4 (g)C2H6 (g)C2H5 (g)C4H10 (g)- 635.1262.3Iron- 50.8Fe (g)Fe (s)Fe2+ (aq)Fe3+ (aq)FeCl2 (s)FeCl3 (s)FeO (s)Fe203 (s)186.3415,5369,8180,5226,7209,2200.827.1552.3068.11219.4-87.86-84.93113.4-84.68-32.89229.5-47.69-10.54293.3-103.85-23.47269.9-341.8- 302.31179-124.73- 15.0310.0- 400- 334142.3- 271.9C4H10 (1)C6H6 (g)C6H6 (1)CH3OH (g)CH3OH (1)C2H5OH (g)C5H5OH (1)C6H1206 (s)CO (g)CO2 (g)HC2H3O2 (1)H2CO (g)НзСCНО (g)CesiumCs (g)Cs (s)CSCI (s)- 147.6- 15.0231.0- 255,260.7582.9129.7269.2-822.16-740.9889.96- 1117.1- 171.5- 1014.2- 160.149.0124.5172.8Fez04 (s)FeS2 (s)146.4-- 201.2- 161.9237.652.92- 238.6-166,23126.8Lead- 235,1- 168.5282.7РЬ (s)PbBr2 (s)68.85- 277,7-174.76160.7- 277.4- 260.7161-1273.02- 910.4212.1РЬСОЗ (s)-6994- 625.5131.0- 110.5- 393,5- 137.2Pb(NO3)2 (aq)Pb(NO3)2 (s)PbO (s)197.9-421,3-246.9303,3- 394.4213.6- 451.9- 487.0- 392.4159.8- 217.3- 187.968.70-116.-110219Lithium-166-133.7266Li (g)Li (s)Lit (g)LICI (s)159,3126.6138,829.0976.5049.53175.6685.7648.5133.085.15- 408.3- 384.059.30- 442.8-414.4101.2

Answered: Image /qna-images/answer/ede05b74-cd39-4f37-aa0c-450f0b62132b.jpg

Use the free energies of formation given below to calculate the equilibrium constant (Keg) for the following reaction at 298 K. 2 A2X (g) 3 Z2 (g) 2 XZ2 (g) + 2 A2Z (g) Keg = ? (The letters shown are theoretical elements) Using the following Data: A2X (g) Z2 (g) XZ2 (g) A2Z (g) AG°f (kJ/mol) -33.4 0.00 -300.1 -228.6 O 1.49 0.670 no right answer O 2,57 103 4.39 -10173

Use the free energies of formation given below to calculate the equilibrium constant (Keg) for the following reaction at 298 K. 2 A2X (g) 3 Z2 (g) 2 XZ2 (g) + 2 A2Z (g) Keg = ? (The letters shown are theoretical elements) Using the following Data: A2X (g) Z2 (g) XZ2 (g) A2Z (g) AG°f (kJ/mol) -33.4 0.00 -300.1 -228.6 O 1.49 0.670 no right answer O 2,57 103 4.39 -10173

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter4: Energy And Chemical Reactions

Section4.6: Reaction Enthalpies For Chemical Reactions

Problem 4.10CE

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