What is a potential problem with the built-in sort used by lists? The built-in sort can fail when there are both float and integer values in a numeric list. O Sort only works with string data. O String values are not sorted alphabetically when upper and lowercase characters are used. O Sort only works with numeric data.

What is a potential problem with the built-in sort used by lists? The built-in sort can fail when there are both float and integer values in a numeric list. O Sort only works with string data. O String values are not sorted alphabetically when upper and lowercase characters are used. O Sort only works with numeric data.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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What is a potential problem with the built-in sort used by lists?
O The built-in sort can fail when there are both float and integer values in a numeric list.
O Sort only works with string data.
O String values are not sorted alphabetically when upper and lowercase characters are used.
O Sort only works with numeric data.
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A sequential search of a sorted list can halt when the target is less than a given element in the list. Modify the program to stop when the target becomes less than the current value being compared. In a sorted list, this would indicate that the target is not in the list and searching the remaining values is unnecessary. ----------------------------------------------------------------------------------- """ File: search.py Project 11.1 """ def sequentialSearch(target, lyst): """Returns the position of the target item if found, or -1 otherwise. The lyst is assumed to be sorted in ascending order.""" position = 0 while position < len(lyst): if target == lyst[position]: return position position += 1 return -1 def main(): """Tests with three lists.""" print(sequentialSearch(3, [0, 1, 2, 3, 4])) print(sequentialSearch(3, [0, 1, 2])) # Should stop at second position. print(sequentialSearch(3, [0, 4, 5, 6])) if…