What is a potential problem with the built-in sort used by lists? The built-in sort can fail when there are both float and integer values in a numeric list. O Sort only works with string data. O String values are not sorted alphabetically when upper and lowercase characters are used. O Sort only works with numeric data.

What is a potential problem with the built-in sort used by lists? The built-in sort can fail when there are both float and integer values in a numeric list. O Sort only works with string data. O String values are not sorted alphabetically when upper and lowercase characters are used. O Sort only works with numeric data.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

in python please
Describe the following list methods:a. indexb. insertc. sortd. reverse
Write a version of the binary search algorithm that can be used to search a list of strings. (Use the selection sort that you designed to sort the list.)
IN PYTHON THANK YOU
ORIGINAL Q: Instead of reading in an entire list N1,N2,⋯N1,N2,⋯ all at once, some algorithms (depending on the task to be done) can read in only one element at a time and process that single element completely before inputting the next one. This can be a useful technique when the list is very big (e.g., billions of elements) and there might not be enough memory in the computer to store it in its entirety. Write an algorithm that reads in a sequence of values v≥0, one at a time, and computes the average of all the numbers. You should stop the computation when you input a value of V = −1. Do not include this negative value in your computations; it is not a piece of data but only a marker to identify the end of the list. PLEASE MODIFY THE FOLLOWING CODE SO THE USER INPUTS THE NUMBERS ONE BY ONE: ORIGINAL Q: Instead of reading in an entire list N1,N2,⋯N1 ,N2,⋯ all at once, some algorithms (depending on the task to be done) can read in only one element at a time and process that single…
In python and the code has to have the methods invoked through Test statements.Built in methods or libraries are not allowed. Sort a DOUBLY linked sequential list using insertion sort algorithma
Complete the reverse_list() function that returns a new string list containing all contents in the parameter but in reverse order. Ex: If the input list is: ['a', 'b', 'c'] then the returned list will be: ['c', 'b', 'a'] Note: Use a for loop. DO NOT use reverse() or reversed(). This is my code so far: def reverse_list(letters): for x in (letters): letters.sort(reverse=True) return lettersif __name__ == '__main__': ch = ['a', 'b', 'c'] print(reverse_list(ch)) # Should print ['c', 'b', 'a'] When submitting I get 4/10 and it says: Test input list ['a', 'b', 'c'] returns ['c', 'b', 'a'] Your output reverse_list() function reversed array incorrectly: ['c', 'b', 'a'] reverse_list() function should have returned: ['a', 'b', 'c'] Test input list ['a', 'b', 'c', 'd'], first element of returned list is ['d'] Your output First character of returned array should be a instead of d Test empty input array TypeError: object of type 'NoneType' has no len()
What happens when your program attempts to access a list element with an invalid index?
TRUE or FALSE? Suppose you have been given a sorted list of 100 names and needed to find a particular name in that list. Using binary search, it is possible that you might have to look at every location in list before finding the desired name
A sequential search of a sorted list can halt when the target is less than a given element in the list. Modify the program to stop when the target becomes less than the current value being compared. In a sorted list, this would indicate that the target is not in the list and searching the remaining values is unnecessary. ----------------------------------------------------------------------------------- """ File: search.py Project 11.1 """ def sequentialSearch(target, lyst): """Returns the position of the target item if found, or -1 otherwise. The lyst is assumed to be sorted in ascending order.""" position = 0 while position < len(lyst): if target == lyst[position]: return position position += 1 return -1 def main(): """Tests with three lists.""" print(sequentialSearch(3, [0, 1, 2, 3, 4])) print(sequentialSearch(3, [0, 1, 2])) # Should stop at second position. print(sequentialSearch(3, [0, 4, 5, 6])) if…
Q15. . requires more memory space than.. Doubly Linked List Doubly Circular Linked List They are all the same