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int[] list = {7,14,26,43,46,50,81} and the length= 7 (binary search Algorithm) use the sorted list above  and fill out the table for 3 different cases: Search for the value that is in the table. Search for the value that is greater than any value in the list. Search for the value that is smaller than any value in the list.

int[] list = {7,14,26,43,46,50,81} and the length= 7 (binary search Algorithm) use the sorted list above  and fill out the table for 3 different cases: Search for the value that is in the table. Search for the value that is greater than any value in the list. Search for the value that is smaller than any value in the list.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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int[] list = {7,14,26,43,46,50,81}

and the length= 7

(binary search Algorithm) use the sorted list above  and fill out the table for 3 different cases:

  • Search for the value that is in the table.
  • Search for the value that is greater than any value in the list.
  • Search for the value that is smaller than any value in the list.
 
The source code is Eprivate static int binarySearch (int[] list, int key, int low, int high) { if (low > high) // The list has been exhausted without a match return -1; int mid = (low + high) / 2; if (key < list[mid]) return binarySearch (list, key, low, mid - 1); else if (key == list[mid]) return mid; else return binarySearch(list, key, mid + 1, high); low high low>high mid=(low+high)/2 Call
Transcribed Image Text:The source code is Eprivate static int binarySearch (int[] list, int key, int low, int high) { if (low > high) // The list has been exhausted without a match return -1; int mid = (low + high) / 2; if (key < list[mid]) return binarySearch (list, key, low, mid - 1); else if (key == list[mid]) return mid; else return binarySearch(list, key, mid + 1, high); low high low>high mid=(low+high)/2 Call
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