def longest_chain (lst: List[int]) -> int: Given a list of integers, return the length of the longest chain of 1's that start from the beginning. You MUST Use a while loop for this, and are not allowed to use a for loop.
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- In c++ Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, th backwards. End each loop with a newline. Ex: If courseGrades (7, 9, 11, 10), print: - 7 9 11 10 10 11 9 7 Hint Use two for loops. Second loop starts with i=NUM VALS-1. (Notes) Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]) See How to Use zyBooks" Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13 14 const int NUM VALS-4; int courseGrades [NUM VALS]; int i; for (i-8; 1 NUM VALS; ++) { cin>> courseGrades[1]; } Your solution goes…Python Lab: Dr.D has invented yet another invention: the hateinator. He wants to test it on a group of N people (numbered 1 through N). The hateinator may be used any number of times; to use it once, Dr.D should divide these N people into two groups and press the fire button on the hateinator. We call each such grouping a Doofish set. Afterwards, there will be hatred between each two people who were in different groups. The hatred does not disappear ― any two people that hate each other before the hateinator is used still hate each other afterwards. The hateinator uses a lot of power. Let's denote the number of times it is used by K. Then, it consumes K⋅N units of power. Dr.D cannot afford to use the hateinator if this number exceeds 106. Dr.D has done the math and computed the most evil hatred system: a situation with some M pairs of people who hate each other. You are given these pairs. There must not be any other pair of people who hate each other. Initially, there is no hatred…Three summers ago def three_summers(items, goal):Given a sorted list of positive integer items, determine whether there exist precisely three separate items that together exactly add up to the given positive integer goal. Sure, you could solve this problem with three nested loops to go through all possible ways to choose three elements from items, checking for each triple whether it adds up to the goal. However, iterating through all triples of elements would get pretty slow as the length of the list increases, seeing that the number of such triples to pick through grows proportionally to the cube of the length of the list! Of course the automated tester will make those lists large enough to make such solutions reveal themselves by their glacial running time. Since items are known to be sorted, a better technique will 0ind the answer significantly faster. See the function two_summers in the example program listproblems.py to quickly find two elements in the given sorted list that…
- This problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints. You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'll need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. 1 def only evens (1st: list[list[int]]) -> list[list[int]]: **"Return a list of the lists in 1st that contain only even integers. 2. 3. >>> only_evens ([[1, 2, 4], [4, e, 6], [22, 4, 3], [2]]) 4. [[4, e, 6], [2]] 8. even_lists = [] 10 for sublist in 1st: 11 12 13 14 return even_lists History Submit P Type here to search 100% 1:1 8°C Cloudy A 4) ENG 10/2This problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints. You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'll need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. def only_evens(lst: list[list[int]]) -> list[list[int]]: """Return a list of the lists in lst that contain only even integers. >>> only_evens([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]]) [[4, 0, 6], [2]] """ even_lists = [] for sublist in lst: # write your code here (please read above for a suggested approach) return even_listsThis problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints.You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'll need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. from typing import List def only_evens(lst: List[List[int]]) -> List[List[int]]: """Return a list of the lists in lst that contain only even integers. >>> only_evens([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]]) [[4, 0, 6], [2]] """ even_lists = [] for sublist in lst: # write your code here (please read above for a suggested approach) return even_lists
- This problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints. You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'll need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. 1 def only_evens (1st: list[list[int]]) -> list[list[int]]: """Return a list of the lists in 1st that contain only even integers. 4 >>> only_evens ([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]]) [[4, 0, 6], [2]] 6. 8. even_lists = [] 10 for sublist in 1st: 11 12 # write your code here (please read above for a suggested approach) 13 14 return even_lists* allSame returns true if all of the elements in list have the same value. * allSame returns false if any two elements in list have different values. * The array may be empty and it may contain duplicate values. * * Your solution should contain at most one loop. You may not use recursion. * Your solution must not call any other functions. * Here are some examples (using "==" informally): * * * * * * * * true == allSame (new double[] { }) true == allSame(new double[] {11}) true == allSame (new double[] { 11, 11, 11, 11 }) false == allSame(new double[] { 11, 11, 11, 22 }) false == allSame (new double[] { 11, 11, 22, 11 }) true == allSame (new double[] { 22, 22, 22, 22 }) * */ public static boolean allSame (double[] list) { return StdRandom.bernoulli(); //TODO: fix this[Python Language] Using loops of any kind, lists, or Sets is not allowed. Sloan’s Book Collection Sloan loves reading books. She recently started reading an AI generated series called “Harry Trotter”. Sloan is collecting books from the series at her nearest bookstore. Since the series is AI generated, the publishers have produced an infinite collection of the books where each book is identified by a unique integer. The bookstore has exactly one copy of each book. Sloan wants to buy the books in the range [l,r], where l ≤ r. As an example, the range [−3,3] means that Sloan wants to buy the books − 3, − 2, − 1, 0, 1, 2, and 3. Pam also loves the series (or maybe annoying Sloan– who knows, really), and he manages to sneak into the bookstore very early to buy all of the books in the range [d,u], where d ≤ u. When Sloan later visits, sadly she will not find those books there anymore. For example, if Sloan tries to buy books [−2,3] and Pam has bought books [0,2], Sloan would only receive…
- QUESTION 4 This is a MULTIPLE ANSWER question, which means you are able to select one or more answers as being correct. Note that this does not necessarily mean that there are multiple correct answers. In any case, select all the answers you believe are correct. (NB: There are no part marks awarded for multiple answer questions.) There is a non-empty Python list of integers called numbera whose values are all in the range -maxaize to maxaize, inclusive. The following piece of code causes the SMALLEST value in list numbers to be stored in the variable answer: best - maxsize t a very large integer for number in numbers: if number number: t a very large integer best = number answer = best + a very small integer best - -maxsize for number in numbers: if best best: best = number answer= best best = -maxsize * a very small integer for number in numbers: if best > number: best - number answer bestPython Programming Lab Dr.D has invented yet another invention: the hateinator. He wants to test it on a group of N people (numbered 1 through N). The hateinator may be used any number of times; to use it once, Dr.D should divide these N people into two groups and press the fire button on the hateinator. We call each such grouping a Doofish set. Afterwards, there will be hatred between each two people who were in different groups. The hatred does not disappear ― any two people that hate each other before the hateinator is used still hate each other afterwards. The hateinator uses a lot of power. Let's denote the number of times it is used by K. Then, it consumes K⋅N units of power. Dr.D cannot afford to use the hateinator if this number exceeds 106. Dr.D has done the math and computed the most evil hatred system: a situation with some M pairs of people who hate each other. You are given these pairs. There must not be any other pair of people who hate each other. Initially, there is no…Three summers ago def three_summers(items, goal): Given a list of positive integer items guaranteed to contain at least three elements with all of its elements in sorted ascending order, determine whether there exist precisely three separate items that together add up to the given positive integer goal, no more and no less. You could, of course, solve this problem with three nested loops to go through all possible ways to choose three elements from items, checking for each triple whether it adds up to the goal. However, this approach would get rather slow as the number of elements in the list increases, and of course the automated tester used to grade this function will make those lists larger just to make such solutions reveal themselves with their excessive consumption of running time. Since items are known to be sorted, better technique will find the answer significantly faster. See the new example function two_summers in listproblems.py to quickly find two elements from the given…