What fraction of the pressure is due to nitrogen? Note: fraction due to nitrogen = N₂ pressure/total pressure = PN₂ / PT What is the nitrogen mole fraction in the tank? Note: mole fraction of nitrogen = moles of N₂ / total moles = = N₂/nT hat is the relationship between the nitrogen pressure ratio in Key Question 4 and the nitrogen ole fraction in Key Question 5? Express this relationship in the form of an equation.
What fraction of the pressure is due to nitrogen? Note: fraction due to nitrogen = N₂ pressure/total pressure = PN₂ / PT What is the nitrogen mole fraction in the tank? Note: mole fraction of nitrogen = moles of N₂ / total moles = = N₂/nT hat is the relationship between the nitrogen pressure ratio in Key Question 4 and the nitrogen ole fraction in Key Question 5? Express this relationship in the form of an equation.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Educational Content: Understanding Pressure and Mole Fraction in a Nitrogen Mixture**
1. **What fraction of the pressure is due to nitrogen?**
*Note:* The fraction due to nitrogen is calculated using the formula:
\[
\text{fraction due to nitrogen} = \frac{\text{N}_2 \text{ pressure}}{\text{total pressure}} = \frac{P_{N_2}}{P_T}
\]
2. **What is the nitrogen mole fraction in the tank?**
*Note:* The mole fraction of nitrogen is determined by:
\[
\text{mole fraction of nitrogen} = \frac{\text{moles of N}_2}{\text{total moles}} = \frac{n_{N_2}}{n_T}
\]
3. **What is the relationship between the nitrogen pressure ratio in Key Question 4 and the nitrogen mole fraction in Key Question 5?**
Express this relationship in the form of an equation.
This educational content explains how to determine the fraction of pressure and mole fraction in a gas mixture, specifically nitrogen, using fundamental equations in chemistry.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F78a96f4b-c4a7-4e44-95dd-3606c481f172%2F3a365c05-525f-49ef-9967-477a591014ed%2Fw2qgah9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Content: Understanding Pressure and Mole Fraction in a Nitrogen Mixture**
1. **What fraction of the pressure is due to nitrogen?**
*Note:* The fraction due to nitrogen is calculated using the formula:
\[
\text{fraction due to nitrogen} = \frac{\text{N}_2 \text{ pressure}}{\text{total pressure}} = \frac{P_{N_2}}{P_T}
\]
2. **What is the nitrogen mole fraction in the tank?**
*Note:* The mole fraction of nitrogen is determined by:
\[
\text{mole fraction of nitrogen} = \frac{\text{moles of N}_2}{\text{total moles}} = \frac{n_{N_2}}{n_T}
\]
3. **What is the relationship between the nitrogen pressure ratio in Key Question 4 and the nitrogen mole fraction in Key Question 5?**
Express this relationship in the form of an equation.
This educational content explains how to determine the fraction of pressure and mole fraction in a gas mixture, specifically nitrogen, using fundamental equations in chemistry.

Transcribed Image Text:**Model: Gases Exert Pressure Independently**
This educational table illustrates how gases exert pressure independently under a controlled environment.
| Condition | Pressure | Volume | Temperature | Comment |
|-----------|----------|--------|-------------|---------|
| Initial | 1.0 atm | 22.4 L | 273 K | 1.0 mole of N₂ gas fills the tank. |
| Final | 3.0 atm | 22.4 L | 273 K | 2.0 moles of O₂ gas have been added to the 1 mole of N₂ gas in the tank. |
**Explanation:**
- **Initial Condition:** At the start, the tank contains 1.0 mole of nitrogen gas (N₂) at a pressure of 1.0 atm, a volume of 22.4 liters, and a temperature of 273 K.
- **Final Condition:** After modifications, the pressure increases to 3.0 atm while keeping the volume and temperature constant. This change results from adding 2.0 moles of oxygen gas (O₂) to the existing nitrogen gas in the tank.
This example demonstrates the concept of partial pressures and how gases in a mixture contribute independently to the total pressure.
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