**MasteringChemistry: Chapter 8 Introduction to Gases - Attempt 1**# Temperature and Volume**Charles's Law** states that the volume of a gas is directly related to the absolute temperature when there is no change in the pressure or amount of gas. This can be represented mathematically as:\[\frac{V_1}{T_1} = \frac{V_2}{T_2}\]**Figure 1 Explanation:**The figure depicts two images of a cylinder with pistons. In the image on the left, labeled "Lower temperature, Smaller volume," the gas molecules are closer together, indicating a smaller volume. There is a small flame underneath the cylinder. The right image, labeled "Higher temperature, Larger volume," shows the gas molecules more spread out after an increase in temperature, indicating a larger volume due to heating. The flame underneath is the same size as in the left image.**Problem Statement:****Part A:**A sample of gas in a balloon has an initial temperature of \(2 \, ^\circ\text{C}\) and a volume of \(1330 \, \text{L}\). If the temperature changes to \(80 \, ^\circ\text{C}\), with no change in pressure or the amount of gas, what is the new volume, \(V_2\), of the gas?*Express the volume numerically in liters.*[Input Box for \(V_2 = \)]*Submit Button***Part B:**What Celsius temperature, \(T_2\), is required to change the volume of the gas sample in Part A \((T_1 = 2 \,^\circ\text{C}, V_1 = 1330 \,\text{L})\) to a volume of \(2660 \,\text{L}\)? Assume no change in pressure or the amount of gas in the balloon.*Express the temperature numerically in degrees Celsius.*[Input Box for \(T_2 = \)]*Submit Button*

For a definite amount of gas, at constant pressure, the volume of the gas increases with an increase in temperature.According to Charles's law, the volume of the gas increases when the temperature of the gas increases. The volume and the temperature are related by the following equation: V1T1=V2T2Part A Where V1 = the initial volume of the gas is= 1330 L V2 = the final volume of the gas =? T1 = the initial temperature of the gas is = 2oC = 2+273.15 = 275.15 K T2 = the final temperature of the gas is = 80oC = 80+273.15 = 353.15 K By rearranging the above equation we get: V2 = V1 × T2T1 Let’s put these values into the above formula to get the final volume of the gas: V2 = 1330 L × 353.15 K275.15 KV2 = 1330 L × 353.15275.15V2 = 1707.03 LV2 = 1707 LPart B Where V1 = the initial volume of the gas is= 1330 L V2 = the final volume of the gas = 2660 L T1 = the initial temperature of the gas is = 2oC = 2+273.15 = 275.15 K T2 = the final temperature of the gas is =? By rearranging the above equation we get: T2 = V2 × T1V1 Let’s put these values into the above formula to get the final volume of the gas: T2 = 2660 L × 275.15 K1330 LT2 = 550.3 KT2 = 550.3-273.15oCT2 =277.15oCT2 =277oC

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Charles's law states that the volume of a gas is directly related to the absolute temperature when there is no change in the pressure or amount of gas: (Figure 1) Figure V₁ K = 1/2 Lower temperature Smaller volume Higher temperature Larger volume 1 of 1 Part A A sample of gas in a balloon has an initial temperature of 2 °C and a volume of 1330 L. If the temperature changes to 80 °C, and there is no change of pressure or amount of gas, what is the new volume, V₂, of the gas? Express the volume numerically in liters. ▸ View Available Hint(s) V₂ = Submit Part B IVE ΑΣΦ T₂ = 3 [5] ΑΣΦ ? What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T₁=2 °C, V₁=1330 L) to a volume of 2660 L ? Assume no change in pressure or the amount of gas in the balloon. Express the temperature numerically in degrees Celsius. ► View Available Hint(s) L °C

Charles's law states that the volume of a gas is directly related to the absolute temperature when there is no change in the pressure or amount of gas: (Figure 1) Figure V₁ K = 1/2 Lower temperature Smaller volume Higher temperature Larger volume 1 of 1 Part A A sample of gas in a balloon has an initial temperature of 2 °C and a volume of 1330 L. If the temperature changes to 80 °C, and there is no change of pressure or amount of gas, what is the new volume, V₂, of the gas? Express the volume numerically in liters. ▸ View Available Hint(s) V₂ = Submit Part B IVE ΑΣΦ T₂ = 3 [5] ΑΣΦ ? What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T₁=2 °C, V₁=1330 L) to a volume of 2660 L ? Assume no change in pressure or the amount of gas in the balloon. Express the temperature numerically in degrees Celsius. ► View Available Hint(s) L °C

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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