The ideal gas law PV = nRT relates pressure P. volume V temperature T. and number of moles of a gas, n. The gas constant Requals 0.08206 L-atm/(K-mol) or 8.3145 J/(K-mol). The equation can be rearanged as follows to solve form n= This equation is useful when dealing with gaseous reactions because stoichiometric calculations involve mole ratios Part A When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction What is the mass of calcium carbonate needed to produce 730 L of carbon dioxide at STP? Express your answer with the appropriate units. View Available in mass of CaCO, Value Submit Part B volume of CO₂ Submit Butane, CH is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is 2CH()+130 (s)-+800(s)+101,0) At 1:00 am and 23°C, what is the volume of carbon dioxide formed by the combustion of 3.40 g of butane? Express your answer with the appropriate units View Available in Provide Feedback A O? Value Units Ca00₂()+Ca0(s) +00₂(x) Units Review Constanta 1 Periodic Table Next >

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Stoichiometric Relationships with Gases**

---

**The Ideal Gas Law**

\[
PV = nRT
\]

This equation relates pressure \(P\), volume \(V\), temperature \(T\), and number of moles \(n\) of a gas. The gas constant \(R\) equals 0.08206 L atm/K mol (or 8.3145 J/(K mol)). The equation can be rearranged to find solutions as follows:

\[
n = \frac{PV}{RT}
\]

This equation is useful when dealing with gaseous reactions because stoichiometric calculations involve mole ratios.

---

**Part A**

When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction:

\[ \text{CaCO}_3(s) \rightarrow \text{CaO}(s) + \text{CO}_2(g) \]

*What is the mass of calcium carbonate needed to produce 73.0 L of carbon dioxide at STP?*  
Express your answer with the appropriate units.

\[
\text{mass of CaCO}_3 = \_\_\_\_ \text{Value} \quad \_\_\_\_ \text{Units}
\]

---

**Part B**

Butane, \( \text{C}_4\text{H}_{10} \), is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is:

\[ 2\text{C}_4\text{H}_{10}(g) + 13\text{O}_2(g) \rightarrow 8\text{CO}_2(g) + 10\text{H}_2\text{O}(g) \]

*At 1.00 atm and 23°C, what is the volume of carbon dioxide formed by the combustion of 3.40 g of butane?*  
Express your answer with the appropriate units.

\[
\text{volume of CO}_2 = \_\_\_\_ \text{Value} \quad \_\_\_\_ \text{Units}
\]

---

[Provide Feedback]

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Transcribed Image Text:**Stoichiometric Relationships with Gases** --- **The Ideal Gas Law** \[ PV = nRT \] This equation relates pressure \(P\), volume \(V\), temperature \(T\), and number of moles \(n\) of a gas. The gas constant \(R\) equals 0.08206 L atm/K mol (or 8.3145 J/(K mol)). The equation can be rearranged to find solutions as follows: \[ n = \frac{PV}{RT} \] This equation is useful when dealing with gaseous reactions because stoichiometric calculations involve mole ratios. --- **Part A** When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction: \[ \text{CaCO}_3(s) \rightarrow \text{CaO}(s) + \text{CO}_2(g) \] *What is the mass of calcium carbonate needed to produce 73.0 L of carbon dioxide at STP?* Express your answer with the appropriate units. \[ \text{mass of CaCO}_3 = \_\_\_\_ \text{Value} \quad \_\_\_\_ \text{Units} \] --- **Part B** Butane, \( \text{C}_4\text{H}_{10} \), is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is: \[ 2\text{C}_4\text{H}_{10}(g) + 13\text{O}_2(g) \rightarrow 8\text{CO}_2(g) + 10\text{H}_2\text{O}(g) \] *At 1.00 atm and 23°C, what is the volume of carbon dioxide formed by the combustion of 3.40 g of butane?* Express your answer with the appropriate units. \[ \text{volume of CO}_2 = \_\_\_\_ \text{Value} \quad \_\_\_\_ \text{Units} \] --- [Provide Feedback] [Next >]
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