Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
What element should go in the empty box in this equation ?
![**Transcription for Educational Website:**
---
**Quiz Question:**
*What element should go in the empty box in this equation?*
**Equation:**
\[
\begin{array}{c}
^{79}_{33}\text{As} \rightarrow ^{0}_{-1}\beta + \square
\end{array}
\]
*10 points*
---
**Explanation of Equation:**
The equation presented is a nuclear reaction involving beta decay. In this process:
- **Beta Particle (\( \beta \)):** The beta particle is represented as \( ^{0}_{-1}\beta \). This indicates the emission of an electron (beta particle) from the nucleus.
- **Arsenic Isotope (\( ^{79}_{33}\text{As} \)):** The arsenic isotope has an atomic number of 33 and a mass number of 79.
**To solve the equation:**
1. **Mass Number Conservation:** The mass number on both sides of the equation must be equal. Arsenic has a mass number of 79. The beta particle has a mass number of 0. Hence, the resulting element will also have a mass number of 79.
2. **Atomic Number Conservation:** The atomic number on both sides must be equal. Arsenic has an atomic number of 33. A beta particle (electron) has an atomic number of -1. Therefore, the resulting element must have an atomic number of 34 (33 - (-1) = 34).
Based on the periodic table, the element with atomic number 34 is Selenium (\( \text{Se} \)).
**Diagram Explanation:**
- The diagram shows the nuclear equation and asks for the missing element in the equation.
- A box is shown in place of the element to be identified.
**Conclusion:**
The element that should go in the empty box in the equation is Selenium (\( ^{79}_{34}\text{Se} \)).
---](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24bf2450-39e8-47a2-b6d3-2df49a54adbe%2F229eb35e-cfb5-4f93-b4fa-c33c98737933%2Fcqd4tbk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website:**
---
**Quiz Question:**
*What element should go in the empty box in this equation?*
**Equation:**
\[
\begin{array}{c}
^{79}_{33}\text{As} \rightarrow ^{0}_{-1}\beta + \square
\end{array}
\]
*10 points*
---
**Explanation of Equation:**
The equation presented is a nuclear reaction involving beta decay. In this process:
- **Beta Particle (\( \beta \)):** The beta particle is represented as \( ^{0}_{-1}\beta \). This indicates the emission of an electron (beta particle) from the nucleus.
- **Arsenic Isotope (\( ^{79}_{33}\text{As} \)):** The arsenic isotope has an atomic number of 33 and a mass number of 79.
**To solve the equation:**
1. **Mass Number Conservation:** The mass number on both sides of the equation must be equal. Arsenic has a mass number of 79. The beta particle has a mass number of 0. Hence, the resulting element will also have a mass number of 79.
2. **Atomic Number Conservation:** The atomic number on both sides must be equal. Arsenic has an atomic number of 33. A beta particle (electron) has an atomic number of -1. Therefore, the resulting element must have an atomic number of 34 (33 - (-1) = 34).
Based on the periodic table, the element with atomic number 34 is Selenium (\( \text{Se} \)).
**Diagram Explanation:**
- The diagram shows the nuclear equation and asks for the missing element in the equation.
- A box is shown in place of the element to be identified.
**Conclusion:**
The element that should go in the empty box in the equation is Selenium (\( ^{79}_{34}\text{Se} \)).
---
Expert Solution
Step 1
We have to determine what element will fill the empty box for the beta decay reaction of As-79 as given below :
In a beta decay reaction, a beta particle is ejected by the nucleus of an element thereby forming a new
nucleus that is more stable.
Step by step
Solved in 3 steps
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