What does the confidence interval suggest about the population means?
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A: We have given that Q1 = 60, Q2 = 84.5, Q3 = 88.5
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Q: In a random sample of 42 Pa high schools it is found that the average number of students is 279.…
A: Given: n=42, x=279 and σ2=206. The value of z at 93% confidence level is 1.81.
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A: Given : n = 27 mean = 4.7 standard deviation = 6.8
Q: ..v.p.v.v.
A: Step 1 Let's break down the steps to determine the correlation coefficient, p-value, and the final…
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A: n1=n2=28 X1-bar=15.2 X2-bar=12.3 S1=2.5 S2=1.9
Q: A learn-to-type software program claims that it can improve your typing skills. To test the claim…
A: Before After 52 47 44 42 40 46 50 43 46 34 38 50
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A: Given that First quartile = Q1 = 24.6
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Q: Refer to Exercise 1. Another molecular biologist repeats the study with a different design. She…
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A: Given Information: Under age of 18 n1=480 x1=160 Over age of 18 n2=500 x2=140
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A: We have given that Sample size n= 40 Favorable cases x = 37 Sample proportion p^=x/n…
Q: A learn-to-type software program claims that it can improve your typing skills. To test the claim…
A: From the provided information, Sample size (n) = 6 Confidence level = 99%
A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded. The summary statistics are as follows.
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- A graduate student is interested in how viewing different types of scenes affects working memory. For his study, he selects a random sample of 36 adults. The subjects complete a series of working memory tests before and after walking in an urban setting. Before the walk, the mean score on the test of working memory was 9.1. After the walk, the mean score was 1.4 higher. The graduate student has no presupposed assumptions about how viewing different types of scenes affects working memory, so he formulates the null and alternative hypotheses as: H00 : μDD = 0 H11 : μDD ≠ 0 Assume that the data satisfy all of the required assumptions for a repeated-measures t test. The graduate student calculates the following statistics for his hypothesis test: Mean difference (MDD) 1.4 Estimated population standard deviation of the differences (s) 1.6 Estimated standard error of the mean differences (sMDMD) 0.2667 Degrees of freedom (df) 35 The t statistic 5.25 The critical values of t…Which of these scenarios means that a pretest-posttest design with a non-equivalent control group is not suitable? Select all that apply. O a. All of the available participants will be receiving the intervention at the same time. O b. Authors want to examine for any trends in the data over time. O c. The participants were placed into the experimental and control groups by natural circumstances rather than random assignment. O d. Authors want to compare averages between two groups before and after the intervention using an ANOVA.In an engineering class, students want to determine the difference in the mean strength between two different types of building materials—Type A, which is relatively inexpensive, and Type B, which is slightly more expensive. The students take a random sample of 60 of the Type A building material and a random sample of 27 of the Type B building material. Given the mean strength for each sample, the students construct a 95% confidence interval for the difference in population means. (a) Determine the degrees of freedom for the conservative approach for finding the t critical value. (b) Find the t critical value associated with 95% confidence. (Use a table or SALT. Round your answer to two decimal places.)
- The class collected their data and found the mean of the dominant forearm maximum force was 34.2 +-3.4 kg . The mean non-dominant forearm maximum force was 28.5 +- 7.8 kg for their 95% confidence intervals. Would you conclude that the means are different?the sample space is {p,q,r,s,t,u,v } with the foll prob 0.1,0.05,0.2,0.3,0.15,0.1 and0.1 L=event {p,q,v} Q= event {q,s,u} R=event{r,t,v,p} find P(Q' interesection R')2 different treatments were used to speed the relief time (in minutes) of migraines. 8 subjects received each treatment. The recovery times are listed below. Treatment 1: 20 19 29 25 34 32 39 38 Treatment 2: 18 18 16 17 29 28 21 37 Construct a 90% confidence interval for the difference in the relief time between the 2 treatments.
- The accompanying technology output was obtained by using the paired data consisting of foot lengths (cm) and heights (cm) of a sample of 40 people. Along with the paired sample data, the technologgy was also given a foot length of 10.8 cm to be used for predicting height. The technology found that there is a linear correlation between height and foot length. If someone has a foot length of 10.8 cm, what is the single value that is the best predicted height for that person? H Click the icon to view the technology output. The single value that is the best predicted height is cm. Technology Output (Round to the nearest whole number as needed.) The regression equation is Height - 67.5 +5.15 Foot Length Predictor Coef SE Coef Constant 67.52 11.07 6.10 0.000 Foot Length 5.1508 0.4817 10.69 0.000 S-5.50271 R-Sq = 73.18 R-Sq (adj) = 72.44 Predicted Values for New Observations New Obs Fit SE Fit 95 CI 954 PI 123.149 1.605 (119.732, 126.566) (111.996, 134.302) Values of Predictors for New…In this exercise involving paired differences, consider that it is reasonable to assume the populations being compared have approximately the same shape and that the distribution of paired differences is approximately symmetric. A sample of 10 men was used in a study to test the effects of a relaxant on the time required to fall asleep. Suppose data for 10 subjects showing the number of minutes required to fall asleep with and without the relaxant follow. Relaxant Subject No Yes 1 14 14 9 2 13 10 3 23 12 4. 6 10 5 9 8 16 8 5 7 00 8 10 8 11 7 9 13 11 10 8 6 Use a 0.05 level of significance to determine whether the relaxant reduces the median time required to fall asleep. State the null and alternative hypotheses. Ho: Median time without relaxant - Median time with relaxant ≤ 0 Ha : Median time without relaxant - Median time with relaxant > 0 O Ho: Median time without relaxant - Median time with relaxant H : Median time without relaxant O Ho: Median time without relaxant - = 0 Median…A learn-to-type software program claims that it can improve your typing skills. To test the claim and possibly help yourself out, you and six of your friends decide to try the program and see what happens. Use the table below to construct an 80% confidence interval for the true mean change in the typing speeds for people who have completed the typing program. Let Population 1 be the typing speed before taking the program and Population 2 be the typing speed after taking the program. Round the endpoints of the interval to one decimal place, if necessary. Typing Speeds (in Words per Minute) Before After 32 33 51 42 55 40 35 32 54 33 45 30 50 52
- In order to determine if weather conditions play a significant role in how a disease effects wheat, fields of wheat are exposed to this disease over three consecutive summers, 2002-2004. The fields are later rated on a scale of 0.0 (resistant) to 10.0 (susceptible) based on how the disease has infected the field. The results are shown below along with the ANOVA table. At the 95% confidence level, compare the mean scores across the three years. 2002 2003 2004 7 7.3 5 4.7 8 3 8 5 2 3.3 3.3 7 6.3 4.7 7.3 7 3.7 8 7 4.3 6. 7 4.3 2 6.3 6.7 ANOVA Source of Variation df MS Treatment 20.97333 2 10.48667 4.127165 Error 76.22667 30 2.540889 Total 97.2 32As a project site civil engineer, you will evaluate the production and process of the concrete producers. You will find that whether the concrete is too watery or not. From the data, the contract specification state that the slump for the concrete used should be 1 inch, with a 90% level of confidence(hint: this is redundant given). So, we will take 10 random samples of fresh concrete and measure the slump. Data: 0.95 1.21 1.03 1.10 1.01 0.99 0.89 0.97 1.01 0.99 Test the hypothesis that mean concrete is different from 1 inch at 10% or 0.10 level of significance. HINT: t-test: two-tailed test. Specify and Use 6 steps method.