What capacitance (in nF (10 F) is needed to store a charge 4.54 µC charge at a voltage of 123 V?
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Q: What capacitance in nF is needed to store a charge of 4.15 uC at a voltage of 106V?
A: Let the charge is denoted by q and the voltage is denoted by V.
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Q: Two sheets of aluminium foil have a separation of 4 mm, a capacitance of 30 pF and are charged to 12…
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A: Step 1: Step 2: Step 3: Step 4:
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A: Charge Q = Capacitance(C) × potential (V) Given C= 5uF Potential V = 2v
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- If the radius is 6.3 cm and the charge is 4.1 µC, how much work was done in charging the sphere? The permittivity of a vacuum is 8.98755 x 10°N m²/C? Answer in units of J.A student is trying to build a home-made capacitor. He uses two 1.0 cm x 1.0 cm aluminum foil as the two parallel conducting plates, spaced 0.40 cm apart. He then connects the two foils with a 3.0 V battery. [Answer in 2 significant figures] a) How many electrons are stored in the negative plate? b) To increase the capacitance, he places a stack of paper (K = 3.6) in between the space and able to decrease the space between the two foils from 0.40 cm to 1.0 mm with the battery still connected. What is the change in energy of the capacitor?Two plates with area 4.00 x 10 m are separated by a distance of 5.90 × 10¬ª m. If a charge of 3.40 x 10-8 C is moved from one plate to the other, calculate the potential difference (voltage) between the two plates. Assume that the separation distance is small in comparison to the diameter of the plates. V potential difference =
- Question 1: a. What is the capacitance of two square parallel plates 15.0 cm x 13.0 cm on sides that are separated by 0.18 mm in air gap.b. Find the dielectric constant K of the paper between two parallel plates with a capacitance Ck = 4.87 nF.A parallel plate capacitor has metal plates, each with an area of 1.5m^2, separated by 1.60mm. What charge is stored in this capacitor if a voltage of 3.2x10^3 V is applied to it?A 0.49-µF capacitor is connected to a 12-V battery. What is the magnitude of the charge on each plate of the capacitor? Group of answer choices 9.22 µC 1.65 µC 5.88 µC 10.1 µC
- Two plates of area 30.0 cm? are separated by a distance of 0.0480 cm. If a charge separation of 0.0640 µC is placed on the two plates, calculate the potential difference (voltage) between the two plates. Assume that the separation distance is small in comparison to the diameter of the plates. potential difference: VHow far from a 1.25 µC point charge is the potential 40.8 V?How much energy is stored in a 56 pF capacitor that has been charged to 12 V? Convert your answer to eV. O 2.5 x 10^10 eV O 4.6 x 10^8 eV 3.8 x 10^9 eV 6.1 x 10^10 eV 8.3 x 10^8 eV
- If the potential due to a point charge is 5.65 kilo-Volts at a distance of 18.5 m, what is the magnitude of the charge in units of micro-Coulombs?The capacitance of a parallel-plate capacitor with plate area A and plate separation d is given by: O Eod/A O ɛod/2A O ɛgA/d O ɛoA/2d O ed/ɛoPoint A is a distance of 0.085 m from a point charge of 0.045 μC. Point B is a distance of 0.225 m from this charge. What is the voltage difference VA-VB? Answer in volts.