An electric field pointing in the positive a di-rection has a magnitude that increases lin-early with a as described by the functionEr = bx, where b = 1 N/C/m.Find the potential difference between thepoints on the x-axis at x =1m and r = 2 m.Answer in units of V.

An electric field pointing in the positiver di- rection has a magnitude that increases lin- early with r as described by the function Er = bx, where b = 1 N/C/m. Find the potential difference between the points on the x-axis at r=1 m and r = 2 m. Answer in units of V. %3|

An electric field pointing in the positiver di- rection has a magnitude that increases lin- early with r as described by the function Er = bx, where b = 1 N/C/m. Find the potential difference between the points on the x-axis at r=1 m and r = 2 m. Answer in units of V. %3|

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter7: Electric Potential

Section: Chapter Questions

Problem 79P: (a) Will the electric field strength between two parallel conducting plates exceed the breakdown...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

An electric field pointing in the positive a di-
rection has a magnitude that increases lin-
early with a as described by the function
Er = bx, where b = 1 N/C/m.
Find the potential difference between the
points on the x-axis at x =1m and r = 2 m.
Answer in units of V.

Expert Solution

Step 1

Solution:

The relation between the electric field and potential difference is given by:

$\vec{E} = - \frac{dV}{dx} Where, E is the electric field and, V is the potential applied$

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