A group of researchers wondered whether vegetarians favored different seasons than non-vegetarians. Theresearchers took a random sample of people and surveyed them about their favorite season and whetheror not they were vegetarian. Here are the responses and partial results of a chi-square test (expectedcounts appear below observed counts):Chi-square test: Dietary restrictions vs.favorite seasonVegetarianNot vegetarianTotalFall78848.475.6Spring55646.457.6Summer1513314814.8133.2Winter58646.457.6Total36324360They want to use these results to carry out a r- test of independence. Assume that all conditions for inference were met.What are the values of the test statistic and P-value for their test?22 = 1.941;0.15< P-value <0.20x= 1.941:P-value> 0.25

We have to conduct a Chi - square test of independence.

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What are the values of the test statistic and P-value for their test?

MATLAB: An Introduction with Applications

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Concept explainers

Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.

Question

A group of researchers wondered whether vegetarians favored different seasons than non-vegetarians. The
researchers took a random sample of people and surveyed them about their favorite season and whether
or not they were vegetarian. Here are the responses and partial results of a chi-square test (expected
counts appear below observed counts):
Chi-square test: Dietary restrictions vs.
favorite season
Vegetarian
Not vegetarian
Total
Fall
78
84
8.4
75.6
Spring
55
64
6.4
57.6
Summer
15
133
148
14.8
133.2
Winter
58
64
6.4
57.6
Total
36
324
360
They want to use these results to carry out a r- test of independence. Assume that all conditions for inference were met.
What are the values of the test statistic and P-value for their test?
22 = 1.941;
0.15< P-value <0.20
x= 1.941:
P-value> 0.25

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