Consider the following competing hypotheses and relevant summary statistics: (You may find it useful to reference the appropriatetable: chi-square table or Ftable)Ho: 01/02 1HA: 02/02 < 1Sample 1: s² = 1,315, and n1Sample 2: s= 1,523, and n2 = 19a. Calculate the value of the test statistic. (Round your answer to 3 decimal places.)Test statisticb-1. Find the p-value.= 17O p-value < 0.01O 0.01 ≤ p-value < 0.025O 0.025 ≤ p-value < 0.050.05 ≤ p-value < 0.10O p-value ≥ 0.10b-2. At a = 5%, what is your conclusion?Reject Ho; we can say that variance 1 is lower than variance 2.Reject Ho; we cannot say that variance 1 is lower than variance 2.O Do not reject Ho; we can say that variance 1 is lower than variance 2.O Do not reject Ho; we cannot say that variance 1 is lower than variance 2.

Test statistic for testing the two variances is given by, F=( s12/n1)/(s22/n2) F=…

Consider the following competing hypotheses and relevant summary statistics: (You may find it useful to reference the appropriate table: chi-square table or Ftable) Ho: 01/02 1 HA: 02/01 Sample 1: s= 1,315, and n₁ = 17 Sample 2: s2 = 1,523, and n2 = 19 a. Calculate the value of the test statistic. (Round your answer to 3 decimal places.) Test statistic b-1. Find the p-value. O p-value < 0.01 O 0.01 ≤ p-value < 0.025 O 0.025 ≤ p-value < 0.05 O 0.05 ≤ p-value < 0.10 O p-value ≥ 0.10 b-2. At a = 5%, what is your conclusion? O Reject Ho; we can say that variance 1 is lower than variance 2. O Reject Ho; we cannot say that variance 1 is lower than variance 2. Do not reject He; we can say that variance 1 is lower than variance 2. O Do not reject Ho; we cannot say that variance 1 is lower than variance 2.

Consider the following competing hypotheses and relevant summary statistics: (You may find it useful to reference the appropriate table: chi-square table or Ftable) Ho: 01/02 1 HA: 02/01 Sample 1: s= 1,315, and n₁ = 17 Sample 2: s2 = 1,523, and n2 = 19 a. Calculate the value of the test statistic. (Round your answer to 3 decimal places.) Test statistic b-1. Find the p-value. O p-value < 0.01 O 0.01 ≤ p-value < 0.025 O 0.025 ≤ p-value < 0.05 O 0.05 ≤ p-value < 0.10 O p-value ≥ 0.10 b-2. At a = 5%, what is your conclusion? O Reject Ho; we can say that variance 1 is lower than variance 2. O Reject Ho; we cannot say that variance 1 is lower than variance 2. Do not reject He; we can say that variance 1 is lower than variance 2. O Do not reject Ho; we cannot say that variance 1 is lower than variance 2.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

You volunteer some of your spare time to your local fire department and have been asked by an assistant chief to analyze data on firefighters who applied for promotion. The assistant chief wants to ensure that gender bias is not a concern in the promotion of firefighters. Shown below is data for 50 firefighters who applied for promotion and the results of a chi-square analysis of the data. Male Female Promoted 13 22 Not Promoted 10 5 Chi-Square Statistic 3.6845 P value 0.054919 What factors should the assistant chief consider in determining the presence of gender bias in firefighter promotion? Is the promotional status of recently promoted firefighters independent of their gender?
You volunteer some of your spare time to your local fire department and have been asked by an assistant chief to analyze data on firefighters who applied for promotion. The assistant chief wants to ensure that gender bias is not a concern in the promotion of firefighters. Shown below is data for 50 firefighters who applied for promotion and the results of a chi-square analysis of the data. Male Female Promoted 13 22 Not Promoted 10 5 Chi-Square Statistic 3.6845 P value 0.054919 Is the promotional status of recently promoted firefighters independent of their gender? What reasons should the assistant chief convey to the fire chief to justify the absence of gender bias in the most recent class of firefighters who were promoted?
Listed below are the overhead widths (in cm) of seals measured from photographs and the weights of the seals (in kg). The purpose of the study was to determine if weights of seals could be determined from overhead photographs. Is there sufficient evidence to conclude that there is a correlation between overhead widths and the weights of the seals? Use a significance level of α=0.05. a. Determine rs. rs= (Round to three decimal places as needed.) b. Determine the critical values. Critical values are (Round to three decimal places as needed. Use a comma to separate answers as needed.)
This question is about interpreting Stata output. You actually do not need to run Stata. Below are some chi- square test results obtained by a researcher: genre gender 2. Total 4 10 3. 10 Total 20 Pearson chi2(2) = 6.3810 Pr = e.041 ) Draw a conclusion. Use the Pearson chi-square result, and 5% as the significant level.
A population has a mean u = 87 and a standard deviation o = 28. Find the mean and standard deviatio sample sizen=49. =(Simplify your answer.) (Simplify your answer.) Enter your answer in each of the answer boxes. ch %3D
The test for the equality of two population variances is based on which of the following? a The ratio of the two sample variances. b The difference between the two population variances. c The difference between the two sample variances. d The ratio of the population variances to the sample variances.
An independent measures study with n = 6 in each sample produces a sample mean difference of 8 points and Sm1-m2= 2. What is the value for the T statistic? A. 1 B. 2 C. 4 D. 4/-8
Find the range, vanance, and standard deviation for the given sample data. Include appropriate units in the results. Listed below are the measured radiation absorption rates (in Wikg) corresponding to various cell phone models. If one of each model is measured for radiation and the results are used to find the measures of variation, are the results typical of the population of cell phones that are in use? 1.16 0.82 0.51 0.69 1.11 0.82 0.69 0.75 0.52 0.53 1.34
Consider the following data: −10, −10, 0, 3, −10, 3, 3 Step 1 of 3: Calculate the value of the sample Variance. Round your answer to one decimal place. Step 2 of 3: Calculate the value of the sample deviation. Round your answer to one decimal place. Step 3 of 3: Calculate the value of the range.
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 59 men and 73 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. SE Mean 1.5 1.7 SIDev 11.2 Mean 112.7 Men Women 99% CI for mu Men - mu Women -11.89, 0.09) T-Test mu Men mu Women (vs<) T= -2.61 P=0.0051 DF 129 59 73 118.6 14.8 Two sample T for Men vs Women State the researcher's condlusion. Which of the following is correct? O A Reject Ha, there is sufficient evidence to condlude that the mean step pulse of men was less than the mean step pulse of women the mean step pulse of women O B. Reject Ha, there is not sufficient evidence to condlude that the mean step pulse of men was less OC. Fail to reject Ho, there is sufficient evidence to conclude that the mean step pulse of men was less than the mean steg pulse of women O D.…
Solve the problem. Find the standardized test statistic t for a sample with n = 15, x = 8.7, s = 0.8, and a = 0.05 if Ho: Hs 8.4. Round your answer to three decimal places. a. 1.452 b. 1.631 c. 1.728 d. 1.312
For scenarios of statistical studies are given below. Decide which study uses a population parameter. And estimated 15% of Americans don't use the Internet. Lakeside family dentistry reported that six of the 15 patients who came in for regular cleaning one day had at least one cavity.