What are the geometry features in the picture below?Indicate main geometry and tolerances 46,3D1B13,2DEDJx45ВA牛D1М5:1EE+0.060,1B10,02 B13,2Unpaaied tolaranoneof dimenalane 2of i80 2788over up to tol.F0.53 +0.16 +0.1Hx30°3M1:130 10.230120 +0.3120 315 10.5GScaleMass0,267 EeMATERIAL2:1SheetCHAIN PINDateWov-21Rev. No Description Sign1/1Des. byChk. byAppr. by234

Geometry Features which mentioned in the Drawing are as below:

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What are the geometry features in the picture below? Indicate main geometry and tolerances

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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0.20 .l 12:42 景令60 ... KB/s laung mateilais, (C) nquius, (u) gases: 9. Suppose a person stated that heat cannot be transferred in a vacuum. How do you respond? 10. Review any standard text on thermodynamics and define: (a) heat, (b) internal energy, (c) work, (d) enthalpy. 11. Define and discuss ge. LIST OF WORKED EXAMPLES 1-1 Conduction through copper plate 1-2 Convection calculation 1-3 Multimode heat transfer 1-4 Heat source and convection 1-5 Radiation heat transfer 1-6 Total heat loss by convection and radiation PROBLEMS 1-1 If 3 kW is conducted through a section of insulating material 0.6 m2 in cross section and 2.5 cm thick and the thermal conductivity may be taken as 0.2 W/m - °C, compute the temperature difference across the material. 1-2 A temperature difference of 85°C is impressed across a fiberglass layer of 13 cm thickness. The thermal conductivity of the fiberglass is 0.035 W/m - °C. Compute the heat transferred through the material per hour per unit area. 1-3 A…
7 Table 1. Saturation: Temperatures Sperie Velume Internal Energy Esthalyy Eatregy 65.37 100as 1192 20 I 101342 190.5 24042 64.20 idie s4 I6 2604I 10I15 1858 24 1021 0 ITRIO 28041 61 102386 1502 2604I 1927 2 I776.2 28040 1028 54 13755 2040 10257 171T1.4 18009 3000 12187 2455E 3.523 4179 240 35071 6170 237 3.171 63.0 1019 2ó išs49 1224 122개 232 3A146 6.159 24 3484 6108 239 386 19. 10332I IST0 26040 10132 I10.5 2803. 58.7 103T90 IM60 260 1042.09 1 7616 280 T 37M 104259 i5612 2603A 1046 756.7 205 S67 1047 2 iss4 2603T 10S 64 1751.7 28014 272)3936 61225 55. 1051.99 1555 260 S 1056.43 1346 2832 3344 240 241 242 243 2.1015 34422 6.14 27101 34260 6.1366 2.7I 340 61296 12291 3463 3.534 3.56 12334 12155 12177 244 27380 3374 61154 54.11 105.7I 15467 2603.4 106.23 L741.7 2803.0 53.75 64 154 2603.2 52.2 6 16 1S3 26030 100 RS 1731 225 S1.0 T08 1339 202 101 6 i1765 28022 S1 0 1075 64 15210 26026 1080 51 7214 28019 245 24 247 24 3.648 3.11 3.776 340 1239 12422 13444 1246 i 249 2.1412 33612 6108)…
y Formül; Tmaks TL -;(1 – 0,630b/a) M,(lzy.z– ly.y) + M,(1..2 – Izy.y) 4.ly – Izy² Oz + Oy, tan20, - J,- dy czab³G' 5>5 için q = 10 cm It 2tA Og+ dy Ox- By cos20 + Tysin20 , Jort 2 2 600 N `x ty =- sin20 + Tyycos20 , Omaks.min 14 cm B Tmaks + rảy Vertical load is applied to point B of a 10 mm radius cylindrical bar as shown in the figure. Calculate the normal stress at point D. 76,39 MPa O MPa 48,86 MPa O 33,37 MPa O 94,75 MPa
What is the enthalpy of steam at 155 deg C? Find the specific enthalpy of superheated steam at 2 atm and 900°C.
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5 -1 -1] If Eij -1 5 -1 then principle st rain values is %3D -1 -1 5 3,5,7 I O 3,6,6 .II O 2,5,8 .III O
2. For superheated water, given a pressure P-0.2 MPa, calculate the internal energy (u) and enthalpy (h) when the temperature is 560 °C. I. TABLE A-6 Superheated watier mkg J/igK P0.20 MPa (12021 C) O.88578 2529.1 0.95986 2577.1 Sat 150 200 250 300 27063 2769.1 2870.7 2971.2 3072.1 32770 34877 37048 39288 41598 43977 4642.3 48933 5150.4 10.0304 5413.1 102029 7.1270 7.2810 7.5081 7.7100 7.5941 8.2236 85153 8.7793 9.0221 92479 9A598 9.6599 1.08049 2654.6 1.19890 273IA 131623 208.8 154934 29672 1.78142 31314 201302 500 302.2 224434 3479.9 247550 700 800 S00 1000 6647 2.70656 38563 201755 1100 1200 1300 40548 3.16848 4259.6 39938 4470.5
9:23 日 52% LIU Hadi Moustafa H 1 ft 4 ft 2 ft A 4 ft. II
Saturation: Pressures Specifie Volume Sa Internal Energy Sal Ligule Entropy Set. Ligurd Enthalpy Pr Tegp Ligld 10, Sat. Vaper Sal. Liquid Sat Veper Sat. Vapor Erap Er 10 DO06113 .0007 COC3 .co09 01 1.0002 206 136 1.89 1.0001 181 255 3.77 1.0001 159 675 5.45- 1.0001 142 789 00 2.75.3 23753 7.90 23700 2377.9 15.81 2364.7 23806 22.88 23600 2382.9 · O1 25013 2501.4 7.91 24969 2504 8 15.81 2492.5 2508.3 22.89 2488 5 2511.4 0000 9.1562 9.1562 0288 9.0775 9,1064 0575 8.9999 9.0573 ON29 8.9312 9,0:42 .0010 0011 0012 0013 .0014 6.98 1.0002 129 208 8.37 1.0002 118 042 9.66 LO003 108 696 10.86 11.98 29.30 2355.7 2385.0 35.17 23518 2386.9 40.58 2348.1 2388.7 45.60 2344.7 23903 50.31 23416 2391.9 29.30 24849 2514.2 35.17 2481.6 2516.8 40.58 2478.6 2519.1 45.60 2475.7 25213 503I 2473.1 2523.4 1059.R8697 8.9756 1268 8.8140 8.9408 1460 8.7631 8.9091 1637 8.7162 8.8799 1802 8.6727 8.8529 1.0004 100 755 1.0005 93 922 54.71 2338.6 2393.3 58.87 2335.8 2394.7 62.80 2333.2 2396.0 66.53 2330.7 23972 70.09…
K2a please help me with my reviewer. Provide me the full solution and answer thank you SN= 40
Solve for the missing values in the following table for refrigerant-134a,
Q1- A wet gas has composition as given below. Determine a value of z-factor for this gas at reservoir conditions of 5709 psig and 293°F. * Composition, mole percent Component Hydrogen sulfide Carbon dioxide Nitrogen Methane Ethane 8.67 Propane i- Butane n-Butane i- Pentane n-Pentane Hexanes 1.40 0.45 79.81 5.28 1.71 0.55 0.53 0.24 0.19 0.24 0.93 Heptanes plus 100.00 Properties of heptanes plus Specific gravity Molecular weight 0.759 132 Ib/lb mole