What amount of thermal energy (in kJ) is required to convert 242 g of ice at -29 °C completely to water vapour at 216 °C? The melting point of water is 0 °C and its normal boiling point is 100 °C. The heat of fusion of water is 6.02 kJ mol-¹ The heat of vaporization of water at its normal boiling point is 40.7 kJ mol-1 The specific heat capacity of ice is 2.09 J g-¹ °C-1 The specific heat capacity of liquid water is 4.18 J g-¹ °C-1 The specific heat capacity of water vapour is 2.01 J g-¹ °C-1 Answer:

Chemistry
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Chapter10: Liquids And Solids
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Problem 102E: A 0.250-g chunk of sodium metal is cautiously dropped into a mixture of 50.0 g water and 50.0 g ice,...
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What amount of thermal energy (in kJ) is required to convert 242 g of ice at -29 °C completely to
water vapour at 216 °C? The melting point of water is 0 °C and its normal boiling point is 100 °C.
The heat of fusion of water is 6.02 kJ mol-1
The heat of vaporization of water at its normal boiling point is 40.7 kJ mol-¹
The specific heat capacity of ice is 2.09 J g-¹ °C-1
The specific heat capacity of liquid water is 4.18 J g¯¹ °C-¹
The specific heat capacity of water vapour is 2.01 J g-¹ °C-¹
Answer:
Transcribed Image Text:What amount of thermal energy (in kJ) is required to convert 242 g of ice at -29 °C completely to water vapour at 216 °C? The melting point of water is 0 °C and its normal boiling point is 100 °C. The heat of fusion of water is 6.02 kJ mol-1 The heat of vaporization of water at its normal boiling point is 40.7 kJ mol-¹ The specific heat capacity of ice is 2.09 J g-¹ °C-1 The specific heat capacity of liquid water is 4.18 J g¯¹ °C-¹ The specific heat capacity of water vapour is 2.01 J g-¹ °C-¹ Answer:
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