What amount of thermal energy (in kJ) is required to convert 221 g of ice at -16 °C completely to water vapour at 214 °C? The melting point of water is 0 °C and its normal boiling point is 100 °C. The heat of fusion of water is 6.02 kJ mol-¹ The heat of vaporization of water at its normal boiling point is 40.7 kJ mol-¹ The specific heat capacity of ice is 2.09 J g¯¹ °C-¹ The specific heat capacity of liquid water is 4.18 J g¯¹ °C-¹ The specific heat capacity of water vapour is 2 01 Lg1-1

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter10: Liquids And Solids
Section: Chapter Questions
Problem 104E: A 0.250-g chunk of sodium metal is cautiously dropped into a mixture of 50.0 g water and 50.0 g ice,...
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What amount of thermal energy (in kJ) is required to convert 221 g of ice at -16 °C
completely to water vapour at 214 °C? The melting point of water is 0 °C and its normal
boiling point is 100 °C.
The heat of fusion of water is 6.02 kJ mol-¹
The heat of vaporization of water at its normal boiling point is 40.7 kJ mol-¹
The specific heat capacity of ice is 2.09 J g-¹ °C-¹
The specific heat capacity of liquid water is 4.18 J g-¹ °C-¹
The specific heat capacity of water vapour is 2.01 Jg¹¹ °C-¹
Answer:
Transcribed Image Text:What amount of thermal energy (in kJ) is required to convert 221 g of ice at -16 °C completely to water vapour at 214 °C? The melting point of water is 0 °C and its normal boiling point is 100 °C. The heat of fusion of water is 6.02 kJ mol-¹ The heat of vaporization of water at its normal boiling point is 40.7 kJ mol-¹ The specific heat capacity of ice is 2.09 J g-¹ °C-¹ The specific heat capacity of liquid water is 4.18 J g-¹ °C-¹ The specific heat capacity of water vapour is 2.01 Jg¹¹ °C-¹ Answer:
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