Refer to this data table: Specific heat of: Molar heat of fusion of ice 6.01 kJ/mol. ice 2.03 J/g °C. Molar heat of vaporization of water = 40.79 kJ/mole steam = 1.99 J/g °C. water = 4.184 J/g °C. Calculate the heat in kJ theoretically required to transform 0.895 kg of ice at 0.00 °C to water at 38.0 °C. 92.3 kJ 263 kJ 822 kJ 318 kJ 194 kJ 710 kJ 74.6 kJ 441 kJ
Ideal and Real Gases
Ideal gases obey conditions of the general gas laws under all states of pressure and temperature. Ideal gases are also named perfect gases. The attributes of ideal gases are as follows,
Gas Laws
Gas laws describe the ways in which volume, temperature, pressure, and other conditions correlate when matter is in a gaseous state. The very first observations about the physical properties of gases was made by Robert Boyle in 1662. Later discoveries were made by Charles, Gay-Lussac, Avogadro, and others. Eventually, these observations were combined to produce the ideal gas law.
Gaseous State
It is well known that matter exists in different forms in our surroundings. There are five known states of matter, such as solids, gases, liquids, plasma and Bose-Einstein condensate. The last two are known newly in the recent days. Thus, the detailed forms of matter studied are solids, gases and liquids. The best example of a substance that is present in different states is water. It is solid ice, gaseous vapor or steam and liquid water depending on the temperature and pressure conditions. This is due to the difference in the intermolecular forces and distances. The occurrence of three different phases is due to the difference in the two major forces, the force which tends to tightly hold molecules i.e., forces of attraction and the disruptive forces obtained from the thermal energy of molecules.
![Refer to this data table:
Specific heat of:
Molar heat of fusion of ice = 6.01 kJ/mol.
ice = 2.03 J/g °C.
Molar heat of vaporization of water = 40.79 kJ/mole
steam = 1.99 J/g °C.
water = 4.184 J/g °C.
Calculate the heat in kJ theoretically required to transform 0.895 kg of ice at 0.00 °C to water at 38.0 °C.
92.3 kJ
263 kJ
822 kJ
318 kJ
194 kJ
710 kJ
74.6 kJ
441 kJ](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7e45d7fa-4a5f-42ab-bc7d-edf291061e2e%2F0ca6aba3-ce2f-41d6-985a-09a32f594045%2F3hn002b_processed.jpeg&w=3840&q=75)
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Given,
Specific heat of
Ice = 2.03 J/g°C
Steam = 1.99 J/g°C
Water = 4.184 J/g°C
Molar heat of fusion of ice = 6.01 kJ/mol
Molar heat of vaporization of water = 40.79 kJ/mol
Mass of ice = 0.895 kg = 895 g
Initial temperature (Ti) = 0.00°C
Final temperature (Tf) = 38.0°C
Amount of heat required to transform 0.895 kg of ice at 0.00°C to water at 38.0°C = ?
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