What amount of energy does it take to assemble a charge configuration consisting of 3 points charges all with a charge of q=6.75 *10^-6 C that are to be arranged into a straight line seperated consecutively by x=0.163 meters?
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A: ∆EK=Ui-Uf=kqQri-kqQrf=kqQ1ri-1rf=9×109 NC5.5×10-6 C49.1×10-6 C119.3×10-2 m-119.3+95.1×10-2 m=10.47 J
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What amount of energy does it take to assemble a charge configuration consisting of 3 points charges all with a charge of q=6.75 *10^-6 C that are to be arranged into a straight line seperated consecutively by x=0.163 meters?
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- Two identical point charges (q=+1.40 x 10-6 C) are fixed at opposite corners of a square whose sides have a length of 0.620 m. A test charge (90 = -4.50 x 108 C), with a mass of 7.40 x 10-8 kg, is released from rest at one of the corners of the square. Determine the speed of the test charge when it reaches the center of the square. Number i Units VB. 90 9In 1910 Rutherford performed a classic experiment in which he directed a beam of alpha particles at a thin gold foil. He unexpectedly observed a few of the particles scattered almost directly backward. This result was not consistent with then current models of atomic structure and led Rutherford to propose the existence of a very dense concentration of positive charge at the center of an atom-the atomic nucleus. The alpha particle has a charge of +2e and the gold nucleus a charge of +79e. Suppose that an alpha particle is initially How close will at a gold nucleus. a great distance from the gold, has a kinetic energy of 3.97 MeV (3.97 x 106 eV), and is headed directly the particle come to the center of the nucleus? Treat the nucleus and the alpha particle as point charges.A very small object with mass 8.20 * 10-9 kg and positive charge 6.50 * 10-9 C is projected directly toward a very large insulating sheet of positive charge that has uniform surface charge density 5.90 * 10-8 C/m2. The object is initially 0.400 m from the sheet. What initial speed must the object have in order for its closest distance of approach to the sheet to be 0.100 m?
- An electric dipole consisting of charges of magnitude 1.90 nC separated by 7.80 μµm is in an electric field of strength 1210 N/C. What are (a) the magnitude of the electric dipole moment and (b) the difference between the potential energies for dipole orientations parallel and antiparallel to E? →> (a) Number i (b) Number Units UnitsA particle of charge +9.5 µC is released from rest at the point x = 62 cm on an x axis. The particle begins to move due to the presence of a charge Q that remains fixed at the origin. What is the kinetic energy of the particle at the instant it has moved 21 cm if (a)Q = +74 µC and (b)Q-74 μC? (a) Number i (b) Number i Units UnitsA particle of charge 7.5 mC is released from rest at the point x 60 cm on an x axis.The particle begins to move due to the pres- ence of a charge Q that remains fixed at the origin. What is the ki- netic energy of the particle at the instant it has moved 50 cm if (a) Q 20 mC and (b) Q 20 mC?
- Three charges, q1 = 1 µC, q2 = 2 µC and q3 = 3 µC are placed in a line with 20 cm between %3D each of them. So qat a = 0, q2 at z = 20 cm and q3 at z = 40 cm. Calculate the energy stored in the collection of charges. (a) -0.62 J (b) -0.43 J (c) +0.43 J (d) +0.62 JA positive point charge q1= +4.00 x10^-4 C is held fixed at the origin. A small object with negative charge q2= -5.00 x10^-5 C is released from rest at a point on the x axis a distance of 0.500 m from q1 and it moves towards q1. What is the kinetic energy of the object when it is .300 m from q1?The charge q = 1.6 X 10-19 C, mass m = 1.7 X 102 kg, potential difference (voltage) = 1 gigavolt (10° V). If the particle starts from rest, calc. the final velocity of the particle. (in units of m/s). %3D %3D (a) 1.3 X 108 (b) 2.3 X 10 (c) 3.3 X 10% (d) 4.3 X 108
- In 1910 Rutherford performed a classic experiment in which he directed a beam of alpha particles at a thin gold foil. He unexpectedly observed a few of the particles scattered almost directly backward. This result was not consistent with then current models of atomic structure and led Rutherford to propose the existence of a very dense concentration of positive charge at the center of an atom—the atomic nucleus. The alpha particle has a charge of +2e and the gold nucleus a charge of +79e. Suppose that an alpha particle is initially a great distance from the gold, has a kinetic energy of 2.31 MeV (2.31 106 eV), and is headed directly at a gold nucleus. How close will the particle come to the center of the nucleus? Treat the nucleus and the alpha particle as point charges.In 1910 Rutherford performed a classic experiment in which he directed a beam of alpha particles at a thin gold foil. He unexpectedly observed a few of the particles scattered almost directly backward. This result was not consistent with then current models of atomic structure and led Rutherford to propose the existence of a very dense concentration of positive charge at the center of an atom-the atomic nucleus. The alpha particle has a charge of +2e and the gold nucleus a charge of +79e. Suppose that an alpha particle is initially a great distance from the gold, has a kinetic energy of 5.44 MeV (5.44 x 106 eV), and is headed directly at a gold nucleus. How close will the particle come to the center of the nucleus? Treat the nucleus and the alpha particle as point charges.Jwo metal spheres, each of radius 4.2 cm, have a center-to-center separation of 1.9 m. Sphere 1 has a charge of + 1.5 x 10 C; sphere 2 has a charge of - 3.4 x 10 C. Assume that the separation is large enough for us to assume that the charge on each sphere is uniformly distributed (the spheres do not affect each other). With V = 0 at infinity, calçulate in volts (a) the potential at the point halfway between their centers and the potential on the surface of (b) sphere 1 and (c) sphere 2. (a) Number i Units (b) Number i Units (c) Number i Units