Identical 53 µC charges are fixed on an x axis at x = + 2.7 m. A particle of charge q = - 19 µC is then released from rest at a point on the positive part of the y axis. Due to the symmetry of the situation, the particle moves along the y axis and has kinetic energy 1.0 Jas it passes through the point x = 0, y = 3.6 m. (a) What is the kinetic energy of the particle as it passes through the origin? (b) At what negative value of y will the particle momentarily stop?

Identical 53 µC charges are fixed on an x axis at x = + 2.7 m. A particle of charge q = - 19 µC is then released from rest at a point on the positive part of the y axis. Due to the symmetry of the situation, the particle moves along the y axis and has kinetic energy 1.0 Jas it passes through the point x = 0, y = 3.6 m. (a) What is the kinetic energy of the particle as it passes through the origin? (b) At what negative value of y will the particle momentarily stop?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

In one of the classic nuclear physics experiments at the beginning of the 20th century, alpha particles were accelerated toward stationary gold nuclei. Some alpha particles were reflected straight back due to the Coulomb interaction between the alpha particle and the nucleus. If the kinetic energy of a doubly charged alpha nucleus was 9.41 MeV when it was a large distance away from the nucleus, how close to the gold nucleus (79 protons) could it come before being reflected? Enter this distance in units of fm = 10-15 m. 1 MeV = 1.6*10-13 J Enter a number with one digit behind the decimal point.
a) What is the electrical potential, in units of Volt, in the rod at x=L/2 ? b) What is the electric-field magnitude E, in units of V/m, in the rod at x=L/2?
Two charges, q1 = 4.5 µC and q2 = 4.5 µC are placed symmetrically along the x-axis at =±3.25 m. Consider a charge q3 of charge 9.1 µC and mass 6.58 µg moving along the y-axis. q3 starts from rest at y= 0.18 m. If the total work on charge q3 is 6.27 J, what is the final speed of the charge?
A particle has a charge of +1.76 μC and moves from point A to point B, a distance of 0.201 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +8.87E-4 J. Calculate the magnitude of the electric force that acts on the particle.
Three point charges lie on the x axis: q1 = 2.00 µC is at x = 0; q2 = 4.00 µC is at x = 2.00 m; q3 is at x = 4.00 m. What is the magnitude of q3 (in µC) if the electric potential energy of the system is zero?
A uranium nucleus fissions in two spherical fragments of charge 38e and 54e and radii 5.5-10-15 m and 6.2 10-15 m, respectively. Assume that the charge is distributed uniformly throughout the volumes, that just before separation each fragment is at rest, and that fragments surfaces are in contact. The electric potential energy of two spherical fragments in MeV (1 MeV = 1.6 10-13 J) is O 1.0 MeV. 220 MeV. 15 MeV. 250 MeV. 80 MeV.
A particle of mass 6 × 10−5kg and charge6 µC moves downward from point A to pointB a distance of 2 m in the earth’s gravitational field. The kinetic energy of the particledecreases by 2.9 mJ during this movement.What is the potential difference VB − VA?The acceleration of gravity is 9.8 m/s2.Answer in units of kV.
Charge q1 = 2 nC is located at the coordinate system origin, while charge q2 = 1.3 nC is located at (a, 0), where a = 1.5 m. The point P has coordinates (a, b), where b = 0.55 m. A third charge q3 = 18.5 nC will be placed later. Part (c) What is the total potential energy U, in joules, of the final configuration of three charges? Answer is not 2.63x10^-7 J
Two tiny metal spheres A and B of masses mA = m and mB = have equal positive charges q. The spheres are connected by a massless nonconducting string of length d, which is much greater than the radii of the spheres. NOTE: Express your answers in terms of m, q, d, and eg. (a) What is the electric potential energy of the system? U = (b) Suppose you cut the string. At that instant, what is the acceleration of sphere A? AA = (c) Suppose you cut the string. At that instant, what is the acceleration of sphere B? Ав (d) A long time after you cut the string, what is the speed of sphere A? VA = (e) A long time after you cut the string, what is the speed of sphere B? UB =
A proton is moving from an initial point A to a final point point B, a distance 0.50 m, in a direction opposite to a uniform electric field of magnitude 6.4 x 104 V/m (see figure). Find the change in this particle's potential energy. Group of answer choices -1.8 x 10^-15 J 1.2 x 10^-15 J +5.1 x 10^-15 J -3.2 x 10^-15 J
A particle with charge 1.60 x 10-19 C enters midway between two charged plates, one positive and the other negative. The initial velocity of the particle is parallel to the plates and along the midline between them (see figure below). A potential difference of 500.0 V is maintained between the two charged plates. If the lengths of the plates are 10.0 cm and they are separated by 2.00 cm, find the greatest initial velocity for which the particle will not be able to exit the region between the plates. The mass of the particle is 21.0 x 10-24 kg. (Enter the magnitude.) m/s 10.0 cm m 2.00 cm Need Help? Read It
A uniform electric field of magnitude 270 V/m is directed in the positive x direction. A +14.0 µC charge moves from the origin to the point (x, y) = (20.0 cm, 50.0 cm). (a) What is the change in the potential energy of the charge field system?(b) Through what potential difference does the charge move?