We would like to calculate the magnitude of the electric potential at a point Pa distance a to right of a square composed of charged rods. 1- +1 + + + + + + Each rod has total charge Q and is length l. The point P is à distance a to right of the mid- point of the right rod. The width of the rods is negligible compared to all other distances in the problem. Which of the following is the correct integral expression for the potential? Hint: set the origin of your coordinates at the center of the square and label the horizon- tal coordinate x' in the integral.

We would like to calculate the magnitude of the electric potential at a point Pa distance a to right of a square composed of charged rods. 1- +1 + + + + + + Each rod has total charge Q and is length l. The point P is à distance a to right of the mid- point of the right rod. The width of the rods is negligible compared to all other distances in the problem. Which of the following is the correct integral expression for the potential? Hint: set the origin of your coordinates at the center of the square and label the horizon- tal coordinate x' in the integral.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

We would like to calculate the magnitude of
the electric potential at a point Pa distance a
to right of a square composed of charged rods.
+ +++ + + +
Each rod has total charge Q and is length I.
The point P is à distance a to right of the mid-
point of the right rod. The width of the rods
is negligible compared to all other distances
in the problem. Which of the following is the
correct integral expression for the potential?
Hint: set the origin of your coordinates at
the center of the square and label the horizon-
tal coordinate x' in the integral.

Q (+')² + (1/2)²)3/2|
1/2
4TEol
1.
(r+1)2+y
I dz
(r+)2+(1/2)²
-1/2
1/2
4meol
-1/2
H/2
dy
-1/2
Q
2.
1
2Teol
V(I+1)? + y²
Q
dy
-1/2
(1² + y²)3/2' ((I + 1)2 + y²)3/2
3.
1/2
r' da
4Teol
-1/2
/2 (+)2+(!/2)²)3/2
N/2
dy
Q
4TEOl
4.
+.
(x2 + y²)3/2 ((x+1)2 + y²)3/2
(+x')dr'
1/2 ((x+')2+(!/2)²)3/2
4TEol
N/2
dy
(x² + y?)3/2
1
1
4TEOl
5.
((r +1)2 + y²)3/2
1/2
dr
4neol
1/2
((* +x')² + (1/2)²)3/2
(मं्ट उत्ततन)
/2
4Teol
6.
ip
-1/2
+ y?
V(z +1)2 +
Q
dr'
-1/2 V(x + x')² +(/2)-
1/2
dr'
7.
1/2
V(I + x')² + (!/2)²

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