We wish to test of hypothesisH0 : μ1 = μ2 vs H1 : μ1 ̸= μ2. (does not equal)Use the significance level α = 0.01.a. Find the value of the test statistic and distribution of the test statistic.b. Find the p-value of the test or rejection region.c. Find the 99% confidence interval of the difference μ2 − μ1.d. Make a conclusion(abcd please) 500 1000 1500 2000balance0EastOSouthregionWestWe wish to compare Balance in 3 different Region.• Region: A factor with levels East, South, and West indicating the individual's geographical location.Balance: Average credit card balance in $.The mean balance for East, South and West are denoted, respectively, by 1, 2 and 3.Data setlibrary (ISLR2)head (Credit)2 3411 No3 8215 Yes## Income Limit Rating Cards Age Education Own Student Married Region Balance## 1 14.891 3606## 2 106.025 6645## 3 104.593 7075## 4 148.924 9504## 5 55.882 4897## 6 80.180 80474 713 362 684 77Yes SouthYesWestNo WestNo WestYes SouthNo South283483514681357569balance <- Credit$Balanceregion Regression modelThe regression equation for ANOVA is given byy = Bo + B₁ + region South + B + regionWest +where ~ N(0,0²). The dummy variables regionSouth and regionWest are created by the 1m () functionand appear in the output below.Fitting the ANOVA model and output from summary() and anova () functionsThe following R code fit the ANOVA model with 1m () function and print outputs from summary() functionand anova () function.anov_out <- lm (balance - region, data = dat)summary (anov_out)**## Call:## 1m (formula = balance - region, data = dat)## Residuals:Min1Q Median3QMax## -531.00 -457.08 -63.25 339.25 1480.50## Coefficients:#### (Intercept)## regionSouth -12.50## regionWest -18.69Estimate Std. Error t value Pr(>1t|)531.0046.32 11.464 <2e-16 ***56.68 -0.22165.02 -0.287## Signif. codes: 0*** 0.001 0.01 0.05 0.11#### Response: balance#### Residual standard error: 460.9 on 397 degrees of freedom## Multiple R-squared: 0.0002188, Adjusted R-squared: -0.004818## F-statistic: 0.04344 on 2 and 397 DF, p-value: 0.9575anova (anov_out)## Analysis of Variance Table##Box plot0.8260.774Df2## region## Residuals 397 84321458 212397Sum Sq Mean Sq F value Pr(>F)18454 9227 0.0434 0.9575boxplot (balance - region, data = dat)

Given information:k= 3 Groups n= 400 Total observation Inference One way ANOVA

We wish to test of hypothesis H0 : μ1 = μ2 vs H1 : μ1 ̸= μ2. (does not equal) Use the significance level α = 0.01. a. Find the value of the test statistic and distribution of the test statistic. b. Find the p-value of the test or rejection region. c. Find the 99% confidence interval of the difference μ2 − μ1. d. Make a conclusion (abcd please)

We wish to test of hypothesis H0 : μ1 = μ2 vs H1 : μ1 ̸= μ2. (does not equal) Use the significance level α = 0.01. a. Find the value of the test statistic and distribution of the test statistic. b. Find the p-value of the test or rejection region. c. Find the 99% confidence interval of the difference μ2 − μ1. d. Make a conclusion (abcd please)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Give a 99.5% confidence interval, for μ₁ n1 = N₂ = 40, x₁ 20, 2.63, S1 1 23.11, s₂ = 0.6 H - - μ2 given the following information. Use Technology Rounded to 2 decimal places.
A sample of 51 stocks traded on the NYSE that day showed that 5 went up.You are conducting a study to see if the proportion of stocks that went up is is significantly less than 0.3. You use a significance level of α=0.02α=0.02.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =
Determine the test statistic
Please answer all parts You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly different from 75% at a significance level of αα = 0.10. According to your sample, 47 out of 58 potential voters prefer Candidate A. For this study, we should use The null and alternative hypotheses would be: H0H0: (please enter a decimal) H1H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. As such, the final conclusion is that ... The sample data suggest that the population proportion is not significantly different from 75% at αα = 0.10, so there is not sufficient evidence to conclude that the proportion of voters who prefer Candidate A is different from 75%. The sample data suggest that the…
An advertising agency is studying social media campaigns and how they impact website traffic. The advertising agency states the average increase in website traffic after a social media campaign is greater than 20 percent. If we would like to test the advertising agency's claim with a hypothesis test using a significance level of α = 0.015, what is the rejection region? Use the graph below to show the rejection region. First, move the blue dot to choose the appropriate test (left-, right, or two- tailed). Then, slide the shaded region(s) to represent the rejection region. Provide your answer below:
The claim is that for 10 AM body temperatures of males, the mean is less than 98.6°F. The sample size is n=39 and the test statistic is t=−4.041. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.01. Question content area bottom Part 1 State the null and alternative hypotheses. H0: μ ▼ greater than> less than< not equals≠ equals= enter your response here H1: μ ▼ greater than> less than< less than or equals≤ not equals≠ equals= greater than or equals≥ enter your response here (Type integers or decimals. Do not round. Do not include the degree symbol in your answer.) Part 2 The test statistic is enter your response here. (Round to two decimal places as needed.) Part 3 The P-value is enter your response here. (Round to three decimal places as needed.) Part 4 Based on the P-value, there ▼ is is not sufficient evidence at a significance level of 0.01 to…
erproduction of uric acid in the body can be an Indication of cell breakdown. This may be an advance indication of illness such as go adult male patlent has taken eleven blood tests for uric acid. The mean concentration was x = 5.30 mg/dl. The distribution of uric rmal, with o = 1.95 mg/dI. a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of ei lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) normal distribution of uric acid uniform distribution of uric acid o is known On is large Oo is unknown (c) Interpret your results in the context of this problem. O The probability that this interval contains the true average uric acid level for this patient is 0.95. O We are 5% confident that the true uric acid level for this patient falls within this interval. O We are 95% confident that the true uric acid level for this patient falls within…
Please answer the incorrect ones only.
You are conducting a study to see if the accuracy rate for fingerprint identification is significantly different from 0.23. You use a significance level of α=0.01 H0:p=0.23 H1:p≠0.23You obtain a sample of size n=228n=228 in which there are 70 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... The sample data support the claim that the accuracy rate for fingerprint identification is different from 0.23. There is not sufficient sample evidence to support the claim that the accuracy rate for fingerprint identification is different from 0.23.
ou intend to estimate a population mean with a confidence interval. You believe the population to have a normal distribution. Your sample size is 6.a.) The degrees of freedom df=df=b.) Use the t-table on page 4 to find the critical value tctc that corresponds to a confidence level of 95%.tc=(Use 4 decimal places)
You are conducting a study to see if the accuracy rate for fingerprint identification is significantly less than 0.72. You use a significance level of α=0.02 H0:p=0.72 H1:p<0.72You obtain a sample of size n=291n=291 in which there are 192 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the accuracy rate for fingerprint identification is less than 0.72. There is not sufficient evidence to warrant rejection of the claim that the accuracy rate for fingerprint identification is less than 0.72. The sample data support the claim that the…
The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less f than 4.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Click the icon to view the display from technology. @ 2 View an example Get more help. W S Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. Ho: =4.00 Mbps H₁: 4.00 Mbps मे Identify the test statistic. (Round to two decimal places as needed.) X # 3 E 80 F3 D C $ 4 Q 20 F4 R F V % 5 FS T G A 6 B MacBook Air F6 Y H & 7 N 8 F7 U C J * 8 M OB. Ho: F10 . : - ; I option Clear all { [ ? 1 + = 11 Check answer F12 } 1 delete return shif C