We will be solving our last problem on graphs together! Here's the problem statement: There are n cities numbered from 0 to n-1. Given the array edges where edges[i] = [fromi, toi, weighti] represents a bidirectional and weighted edge between cities fromi and toi, and given the integer distanceThreshold. Return the city with the smallest number of cities that are reachable through some path and whose distance is at most distanceThreshold, If there are multiple such cities, return the city with the greatest number. Notice that the distance of a path connecting cities i and j is equal to the sum of the edges' weights along that path. Constraints: 2 <= n <= 100 1 <= edges.length <= n * (n - 1) / 2 edges[i].length == 3 0 <= fromi < toi < n 1 <= weighti, distanceThreshold <= 10^4 All pairs (fromi, toi) are distinct. please code in java and python
We will be solving our last problem on graphs together! Here's the problem statement: There are n cities numbered from 0 to n-1. Given the array edges where edges[i] = [fromi, toi, weighti] represents a bidirectional and weighted edge between cities fromi and toi, and given the integer distanceThreshold. Return the city with the smallest number of cities that are reachable through some path and whose distance is at most distanceThreshold, If there are multiple such cities, return the city with the greatest number. Notice that the distance of a path connecting cities i and j is equal to the sum of the edges' weights along that path. Constraints: 2 <= n <= 100 1 <= edges.length <= n * (n - 1) / 2 edges[i].length == 3 0 <= fromi < toi < n 1 <= weighti, distanceThreshold <= 10^4 All pairs (fromi, toi) are distinct. please code in java and python
Related questions
Question
We will be solving our last problem on graphs together! Here's the problem statement:
There are n cities numbered from 0 to n-1. Given the array edges where edges[i] = [fromi, toi, weighti] represents a bidirectional and weighted edge between cities fromi and toi, and given the integer distanceThreshold.
Return the city with the smallest number of cities that are reachable through some path and whose distance is at most distanceThreshold, If there are multiple such cities, return the city with the greatest number.
Notice that the distance of a path connecting cities i and j is equal to the sum of the edges' weights along that path.
Constraints:
- 2 <= n <= 100
- 1 <= edges.length <= n * (n - 1) / 2
- edges[i].length == 3
- 0 <= fromi < toi < n
- 1 <= weighti, distanceThreshold <= 10^4
- All pairs (fromi, toi) are distinct.
please code in java and python
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)