[4.1] Consider the number -1.36875 x 10¹ as the dividend and 5.625 x 10¹ as the divisor.a. Find their binary representation.b. Normalize the results that you got it in (A) and put them in the 8-bit quarter-precision format (1 for sign bit, 2 for exponent, and 5 for fraction).c. Implement the division and show all the steps of the division to results that you got itin (B). Show if there is an overflow or underflow by assuming that there is a guardbit, a round bit, and a sticky bit.

Binary numbers, sometimes referred to as base-2 numbers, are a type of number representation that…

Answered: [4.1] Consider the number -1.36875 x…

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Description Find the sum of 10.2510 and 5.2510 using the 14-bit "simple" floating-point model. Hint: Refer to slides or class notes for a similar example.
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In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation).…
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