We have that y*n+1=y*n=y*. Using the given model: yn+1 = byn(1-yn),     we find that y* = 1-1/b and y* = 0  are fixed points. I have the function: def main(b,yInit,n):             out=np.zeros((n,1))         y = yInit    for i in range(n):    out[i] = y    y = b*(1-y)*y    return out The graph model of this would depend both on the value of the initial population (y*) and choice of b. I need to graph this in python using interactive sliders widget [from matplotlib.widgets import slider], where one slider will control b value (x-axis) and another for y value (y-axis). I have the skeleton code for the sliders but have no idea how to graph this equation with it. (y* =  between 0 to 1,  b = 0 to 4)

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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We have that y*n+1=y*n=y*. Using the given model: yn+1 = byn(1-yn),     we find that y* = 1-1/b and y* = 0  are fixed points.

I have the function:
def main(b,yInit,n):         

   out=np.zeros((n,1))     

   y = yInit

   for i in range(n):

   out[i] = y

   y = b*(1-y)*y

   return out

The graph model of this would depend both on the value of the initial population (y*) and choice of b.

I need to graph this in python using interactive sliders widget [from matplotlib.widgets import slider], where one slider will control b value (x-axis) and another for y value (y-axis). I have the skeleton code for the sliders but have no idea how to graph this equation with it. (y* =  between 0 to 1,  b = 0 to 4)

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