ose cells and those with value 1 are open. Input Format Line 1: Integer N Next N Lines: Each line will contain ith row elements (separated by space) Output Format : The output line contains true if any path exists for the rat to reach its destination otherwise print false. Sample Input 1 :
You are given a N*N maze with a rat placed at maze[0][0]. Find whether any path exist that rat can follow to reach its destination i.e. maze[N-1][N-1]. Rat can move in any direction ( left, right, up and down).
Value of every cell in the maze can either be 0 or 1. Cells with value 0 are blocked means rat cannot enter into those cells and those with value 1 are open.
Input Format
Line 1: Integer N
Next N Lines: Each line will contain ith row elements (separated by space)
Output Format :
The output line contains true if any path exists for the rat to reach its destination otherwise print false.
Sample Input 1 :
3
1 0 1
1 0 1
1 1 1
Sample Output 1 :
true
Sample Input 2 :
3
1 0 1
1 0 1
0 1 1
Sample Output 2 :
false
Solution: ////
public class Solution {
public static boolean ratInAMaze(int maze[][]){
int n = maze.length;
int path[][] = new int[n][n];
return solveMaze(maze, 0, 0, path);
}
public static boolean solveMaze(int[][] maze, int i, int j, int[][] path) {
// Checking if the current cell which we are going to traverse is a valid cell or not?
if (i < 0 || i >= maze.length || j < 0 || j >= maze.length || maze[i][j] == 0 || path[i][j] == 1) {
return false;
}
// Including the current cell to be in path[i][j]
path[i][j] = 1;
// Checking if the current cell is destination cell or not
if (i == maze.length - 1 && j == maze.length - 1) {
// printing the path before returning
return true;
}
// Explore further the maze in all direction
// Top Direction
if (solveMaze(maze, i - 1, j, path)) {
return true;
}
// Right Direction
if (solveMaze(maze, i, j + 1, path)) {
return true;
}
// Bottom Direction
if (solveMaze(maze, i + 1, j, path)) {
return true;
}
// Left Direction.
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