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We have found that the volume of solution in the tank at time t is given by 400 + t. Let A(t) be the amount of sa A(t) 400 +t the concentration of salt at time t is given by the ratio Recall that solution is pumped out at a rate of 2 Therefore, the rate (in Ib/min) that salt is removed from the tank is as follows. Rout = (concentration of salt removed) · (2 gal/min) A(t) gal (2 gal/min) 400 +t %3D Ib/min 400

We have found that the volume of solution in the tank at time t is given by 400 + t. Let A(t) be the amount of sa A(t) 400 +t the concentration of salt at time t is given by the ratio Recall that solution is pumped out at a rate of 2 Therefore, the rate (in Ib/min) that salt is removed from the tank is as follows. Rout = (concentration of salt removed) · (2 gal/min) A(t) gal (2 gal/min) 400 +t %3D Ib/min 400

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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We have found that the volume of solution in the tank at time t is given by 400 + t. Let A(t) be the amount of salt in the tank at timet, measured in pounds. Then the concentration of salt at time t is given by the ratioA(E) 400 +t Recall that solution is pumped out at a rate of 2 gal/min. Therefore, the rate (in Ib/min) that salt is removed from the tank is as follows. Rout = (concentration of salt removed) · (2 gal/min) - ( Ib/gal : (2 gal/min) A(t) %3D 400 + t Ib/min 400+t
Transcribed Image Text:We have found that the volume of solution in the tank at time t is given by 400 + t. Let A(t) be the amount of salt in the tank at timet, measured in pounds. Then the concentration of salt at time t is given by the ratioA(E) 400 +t Recall that solution is pumped out at a rate of 2 gal/min. Therefore, the rate (in Ib/min) that salt is removed from the tank is as follows. Rout = (concentration of salt removed) · (2 gal/min) - ( Ib/gal : (2 gal/min) A(t) %3D 400 + t Ib/min 400+t
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