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Answered: Ө = 1 "max S Ks+S Solving for substrate…

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter3: Polynomial Functions

Section3.5: Mathematical Modeling And Variation

Problem 7ECP: The kinetic energy E of an object varies jointly with the object’s mass m and the square of the...

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In physics, the kinetic energy, K, of an object of mass m, moving at a velocity v, is given by the equation K = (1/2)mv^2 . If the mass is increasing at a rate of 1 kg per second, and the velocity is decreasing at a rate of 1 meter per second per second, what is the rate of change of the kinetic energy when the mass is 5 kg and the velocity is 2 meters per second?
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(1^0) V (1^1) =
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Ө = 1 "max S Ks+S Solving for substrate (BOD) concentrati -kd