We found that salt is added to the tank at a constant rate and it is removed from the tank at a rate dependent on the concentration of salt in the tank at time t, as follows. R. = 9 lb/min 2A(E) Ib/min Rout = 400 + t We were originally asked to find the total rate of change of salt in the tank as solution is added to the tank at one rate and removed from the tank at another rate. dA = (input rate of salt) - (output rate of salt) dt Therefore, a differential equation (in Ib/min) for the amount of salt A(t) (in Ib) in the tank at time t> 0 is the following. (Use A for A(t).) dA Ib/min dt
We found that salt is added to the tank at a constant rate and it is removed from the tank at a rate dependent on the concentration of salt in the tank at time t, as follows. R. = 9 lb/min 2A(E) Ib/min Rout = 400 + t We were originally asked to find the total rate of change of salt in the tank as solution is added to the tank at one rate and removed from the tank at another rate. dA = (input rate of salt) - (output rate of salt) dt Therefore, a differential equation (in Ib/min) for the amount of salt A(t) (in Ib) in the tank at time t> 0 is the following. (Use A for A(t).) dA Ib/min dt
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:We found that salt is added to the tank at a constant rate and it is removed from the tank at a rate dependent on the concentration of salt in the tank at time t, as
follows.
Rn = 9 lb/min
2A(t) Ib/min
400 +t
Rout =
We were originally asked to find the total rate of change of salt in the tank as solution is added to the tank at one rate and removed from the tank at another rate.
dA
= (input rate of salt) - (output rate of salt)
dt
Therefore, a differential equation (in Ib/min) for the amount of salt A(t) (in Ib) in the tank at time t> 0 is the following. (Use A for A(t).)
dA
Ib/min
dt
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