We have an experiment that launches balls from a height of 2m above a table. One ball is launched in the horizontal direction, one is dropped from rest, and one is launched at an angle of 35 degrees above the horizontal (all from the same initial height). Is it possible for all three balls to reach the ground at the exact same time? If so, what initial velocities would the ball shot horizontally and the ball launched at an angle need to have? Bonus: what is each ball's velocity just before it hits the ground?
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There is only vertical acceleration which is due to earth's gravity, there is no horizontal velocity. In this problem the horizontal component of the velocity, if any, will just lead to uniform horizontal motion. So we would concentrate on the vertical aspect of motion of the three balls.
1st ball : launched in the horizontal direction. Its initial vertical velocity is 0. Acceleration is 'g', distance to be covered is -2 m (taking launching position to be the zero)
2nd ball: Dropped from rest. Again its initial vertical velocity is 0. Acceleration is 'g', distance to be covered is -2 m (taking launching position to be the zero)
3rd ball: Launched at an angle of 350 say with an initial velocity V. Therefore the vertical component of the velocity say U=Vsin. Acceleration is '-g', distance to be covered is -2 m (taking launching position to be the zero)
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