We discussed how to trace the rays through a lens to find the location of an object. Based on this I want you to explain how we would use the same principles to find the image produced by both converging and diverging mirrors. Feel free to create and upload an image to help illustrate the point.
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We discussed how to trace the rays through a lens to find the location of an object. Based on this I want you to explain how we would use the same principles to find the image produced by both converging and diverging mirrors. Feel free to create and upload an image to help illustrate the point.
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- When considering the location of images formed by lenses, we often like to employ ray tracing diagrams. To do this we draw three rays of light and see where they intersect. 1. A ray parallel to the axis refracts through the far focal point. 2. A ray that enters the lens along a line through the near focal point emerges parallel to the axis. 3. A ray through the center of the lens does not bend. This method was shown to you in class for the following situation: An object and converging lenses with the distance to the object being greater than the focal length, do > f. object focal point do focal point Now you will complete the ray tracing diagram for an object that is closer than the focal length: de focal point image Answer the following based on your ray tracing: (a) Is the image real or virtual? (b) is the image larger or smaller than the object? focal pointUsing the simulation as guidance https://simbucket.com/lensesandmirrors/ Choose converging lens of focal length 20 cm. Use tabs ray 1 and ray 2 to see light rays for each of the following object distances. Trace ray diagrams for object distance of 5 and 25 cm. *The diagram needs to be hand-drawnHelp.
- Two plane mirrors are at an angle of ?1 = 53.6° with each other as in the side view shown in the figure below. If a horizontal ray is incident on mirror 1, at what angle ?2 does the outgoing reflected ray make with the surface of mirror 2? Answer in degrees °A ray of light is passed through a ruby and it hits a surface in contact with air (n = 1.000) at an angle of 45° with respect to the normal. Use the table below to determine happens when it hits the surface? What is the critical angle? The ray refracts into the air at an angle of 45° with respect to the normal. The ray reflects back into the ruby at an angle of 45° with respect to the normal. The ray refracts at an angle of 90° with respect to the normal, along the surface. The ray is absorbed in the air. None of the above.A concave mirror (f= +12.5 cm) creates a virtual image of an 5.3 cm tall object. If di is -18.3 cm, where is the object located? Determine the magnification of the mirror in this case. Show your work.
- Please help me on this problem! And show the work step by step, thank you!!Part A A converging lens with a focal length of 60 cm and a diverging lens with a focal length of -50 cm are 290 cm apart. A 3.5-cm-tall object is 80 cm in front of the converging lens. Calculate the image position relative to the diverging lens. Express your answer to two significant figures and include the appropriate units. Enter a positive value if the image is on the other side from the lens and a negative value if the image is on the same side. HẢ ? s'2 Value Units %D Submit Request Answer Part B Calculate the image height. Express your answer to two significant figures and include the appropriate units. HA h' = Value Units %3D Submit Request AnswerExplain how to find the answer for this one please.