Two converging lenses with focal lengths of 40 cm and 21 cm are 12 cm apart. A 4.0-cm-tall object is 15 cm in front of the 40-cm-focal-length lens. Calculate the position of the final image (relative to the 21-cm-focal-length lens). Express your answer to two significant figures and include the appropriate units. Enter a positive value if the image is on the other side from the lens and a negative value if the image is on the same side.
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- Problem 8: Consider the compound optical system shown in the diagram, where two thin lenses of focal lengths 7.5 cm (left lens) and 7.5 cm (right lens) are separated by a distance 45 cm. a. If an object is placed a distance do = 17.3 cm to the left of the first lens (the left one) as shown in the figure, how far to the right of that lens, in centimeters, is the image formed? b. What is the magnification of the first lens? c. What is the object distance, in centimeters, for the second lens (the right lens)? d. What is the image distance, in centimeters, for the second lens? e. What is the magnification of the second lens?The figure shows an object and its image formed by a thin lens. Assume that d1 = 0.552 m, d2 = 0.398 m, and h = 7.50E-2 m. What is the focal length of the lens (in m; answer sign and magnitude)?A convergent lens of focal length 19 cm gives a real image that is 3.1 times larger than the object. Calculate the distance between the object and the lens, in centimeters.
- Consider two thin lenses with focal lengths f1=10.0cm and f2=-15.0cm. The lenses are placed in contact. Calculate the equivalent focal length of the lenses. What is the image distance of an object placed 20.0cm from the lenses? Draw a diagram of the optical system and label the relevant quantities (s0,si,f).A camera with a 70 mm lens takes a photograph of a 2.10 m-tall object located 46 m away. Calculate the height of the image (in mm) on the film. Enter the numerical part of your answer to one decimal figure. Hint: Remember that the sign of the magnification is significant.A lighted candle is placed 36 cm in front of a converging lens of focal length fi = 13 cm, which in turn is 56 cm in front of another converging lens of focal length f2 = 16 cm. (Figure 1) Calculate the position of the final image. Express your answer to two significant figures and include the appropriate units. ? di = Value Units beyond the second lens Figure 1 of 1 Calculate the relative size of the final image. fi = 13 cm 2 = 16 cm %3D Express your answer using two significant figures. - 36 cm 56 cm m = h. ||
- A convex lens has a focal length of 13 cm. A candle with a height of 7 cm is 7 cm away from the lens. Find the location of the image. If the image is real give a positive answer and a virtual image should be a negative answer.- 25 cm. An object of height 2.8 cm is placed at 28 cm in front of a diverging lens of focal length, ƒ = Behind the diverging lens, there is a converging lens of focal length, f = 25 cm. The distance between the lenses is 3 cm. In the next few steps, you will find the location and size of the final image. Hint a. Where is the intermediate image formed by the first diverging lens? Image distance from first lens is cm. (Use the sign to indicate which side the image is on; positive sign di1 = means image is on the side of outgoing rays, and negative sign means image is on the side opposite to the outgoing rays.) b. Where is the final image formed by the second converging lens? Image distance from second lens is cm. (Use the sign to indicate which side the image is on.) d₁2 = c. How large is the intermediate image formed by the first diverging lens? Intermediate image height is cm. (Use the sign to indicate whether the image is upright (positive) or hil = inverted (negative).) = d. How…You hold a magnifying glass 4.0 cm above 1.98 mm-long bug and the image is 5.44 mm long. What is the focal length of the lens? Please give your answer in cm.
- An object of height 7.91cm is placed 40 cm from a converging lens of focal length 11.1 cm. How big is the image? (hint: you should find the image distance first) To continue, enter your answer in cm. Round your answer to 1 decimal place.A certain lens has a focal length of +20cm. How far from the lens must an object be placed so that it produces an image with a magnification of -1.37? Is the image real or virtual?A thin converging lens has a focal length of 8.00 cm. If a real, inverted image is located 12.0 cm from the lens, where is the object located? What is the magnification?