We are interested in understanding how much people know about organic dark chocolate compared to organic milk chocolate. What is our hypothesis set? H0: μdc-μm>0, Ha: μdeμmc H0: μdc-μmc=0, Ha: μdc<μmc H0: μdc-μmc=0, Ha: μdc-μmc+0 H0: μdc-μmc=0, Ha: μdcμmc
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- Iron is an integral part of many proteins and enzymes that maintain good health. Recommendations for iron were developed by an institute of medicine for a certain region. The recommended dietary allowance (RDA) of iron for adult females under the age of 51 years is 17.5 milligrams (mg) per day. A hypothesis test is to be performed to decide whether adult females under the age of 51 years are, on average, getting more than the RDA of 17.5 mg of iron per day. Complete parts (a) through (c). a. Determine the null hypothesis. Ho: H mg (Type an integer or a decimal. Do not round.)The recommended intake for Calcium for adults is 1000 mg per day. A researcher is interested to determine if adults with high income level have more calcium intake than the recommended amount. A hypothesis test is conducted. What is the alternative hypothesis?Foot ulcers are common problem for people with diabetes. Higher skin temperatures on the foot indicate an increased risk of ulcers. The article “An Intelligent Insole for Diabetic Patients with the Loss of Protective Sensation" (Kimberly Anderson, M.S. Thesis, Colorado School of Mines), reports measurements of temperatures, in °F, of both feet for 18 diabetic patients. The results are presented in the Table Q1. Table Ql: Measurements of temperatures, in °F of left foot Vs right foot for 18 diabetic patients Left Foot Right Foot Left Foot Right Foot 80 80 76 81 85 85 89 86 80 86 75 87 82 88 78 78 89 87 80 81 87 82 87 82 78 78 86 85 88 89 76 80 89 90 88 89 (d) Test the slope, ß1 = 1 at 5% level of significance. (e) Calculate the coefficient of correlation r and r2 and then interpret their values
- Gn. Don't provide handwriting solutionK Iron is an integral part of many proteins and enzymes that maintain good health. Recommendations for iron were developed by an institute of medicine for a certain region. The recommended dietary allowance (RDA) of iron for adult females under the age of 51 years is 19 milligrams (mg) per day. A hypothesis test is to be performed to decide whether adult females under the age of 51 years are, on average, getting more than the RDA of 19 mg of iron per day. Complete parts (a) through (c). a. Determine the null hypothesis. Hou mg (Type an integer or a decimal. Do not round.) b. Determine the alternative hypothesis. Ha: H mg (Type an integer or a decimal. Do not round.) c. Classify the hypothesis test as two tailed, left tailed, or right tailed. The hypothesis test is specified value Ho. because the test is deciding whether the population mean is Time Remaining: 01:48:24 the NextFoot ulcers are common problem for people with diabetes. Higher skin temperatures on the foot indicate an increased risk of ulcers. The article “An Intelligent Insole for Diabetic Patients with the Loss of Protective Sensation" (Kimberly Anderson, M.S. Thesis, Colorado School of Mines), reports measurements of temperatures, in °F, of both feet for 18 diabetic patients. The results are presented in the Table QI. Table Q1: Measurements of temperatures, in °F of left foot Vs right foot for 18 diabetic patients Left Foot 80 foo Right Foot Right Foot 81 Left Foot (a) berature m80 85 76 85 89 86 9 marks) 75 80 87 82 88 foot temper 86sof 89 would thei 87 ht foo temp 80ures will 78s differ by 278reespredict by 81 (b) 87 82 87 82 I marks) 78 right foot to9erature for 76 tient whose 0 foot tmperature 78 86 85 (c) 88 89 90 88 89 (I marks) (d) Test the slope, ß1 = 1 at 5% level of significance. (e) Calculate the coefficient of correlation r and r² and then interpret their values
- why it was converted to RCS?The DENR has a new procedure to detect algal bloom in water being tested. This new procedure is important because, it could be used to detect three different contaminants-organic pollutants, volatile solvents, and chlorinated compounds. The department claims that it can detect high levels of organic pollutants with 99.95% accuracy, volatile solvents with 89.70% accuracy, and chlorinated compounds with 99.70% accuracy. If an algal bloom is not present, the test does not signal. Samples are prepared for the calibration of the test and 60% of them are contaminated with organic pollutants, 27% with volatile solvents, and 13% with traces of chlorinated compounds. A test sample is selected randomly. Denote as follows: S = signal, O = organic pollutants, V = volatile solvents, C = chlorinated compounds. If the test signals, what is the probability that chlorinated compounds are present? (Show complete solution in your answer sheet) O a. P(CIS) = 0.1386 Ob.P(C|S) = 0.1184 OC. None among the…Arsenic is a chemical element that occurs in many minerals, usually in conjunction with sulfur and metals, and also as a pure elemental crystal. The main use of metallic arsenic is for strengthening alloys of copper and lead. Unfortunately, arsenic occurs in some ground water. In large quantities it is toxic for multicellular life. A mean arsenic level of 8 particles per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton crops. This well is tested regularly for arsenic. A random sample 37 tests gave a sample mean of 7.2 ppb arsenic with standard deviation of 1.9 ppb. Assume that arsenic levels are normally distributed. We are to use the sample data and test if mean arsenic level in the well in question is less than 8 ppb. a. Test statistic isb. The ? − value of the test isc. At the significance level calculated in part c), we conclude that mean arsenic level in thewell is
- A sociologist wants to determine if the life expectancy of people in Africa is less than the life expectancy of people in Asia. The data obtained is shown in the table below. Africa Asia = 63.3 yr. 1 X,=65.2 yr. 2 o, = 9.1 yr. = 7.3 yr. n1 = 120 = 1505. A study assessed the lung destructive index among smokers and non-smokers provided the following data: X1 - 14 5 "1 =10 n-10 Sp= 1.50 Smokers: %3D X2-12.5 n2 8 a = ,01 %3D Non-Smokers: From the available data, can we conclude that smokers have greater lung damage than non-smokers?A study published by Babcock and Marks (2010) showed that the average full-time U.S. college student studied for μ = 14 hours per week (SD = 4.8 hours per week) in 2005. We want to know if this average has changed in the past 15 years. In other words, we are going to do a study in which we try to determine whether there has been an impact of the passage of time on the amount of time college students spend studying. We selected a sample of n = 64 of today’s college students and find that they spent an average of M = 12.5 hours per week studying. Does this sample indicate a significant change in the number of hours spent studying? Use a two-tailed test (this means non-directional hypothesis) with α = .05.