Vitamin A was administered to children in third world countries to decreasemortality rates. Two hundred children received vitamin A and 160 children did not receive vitaminA. The mortality rate for the Vitamin A group was 6% (12 out of 200). The mortality rate for theNo Vitamin A group was 9.375% (15 out of 160). Are these proportions significantly different? Doa hypothesis test by calculate the chi-square statistic. Then state the appropriate critical value;then come to a conclusion concerning the null hypothesis; and then state what this means withregards to Vitamin A and mortality rates. You must explain every single step you take or no credit.Let the significance level equal 5%.

The given data can be tabulated as follows:

Answered: Vitamin A was administered to children…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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According to the Pew research center 65% of US adults believe that the government should play a larger role in addressing climate change. A random sample (SRS) of 80 US adults found that 56 US adults believe that the government should play a larger role in addressing climate change. Does this indicate that population proportion of US adults who believe that the government should play a larger role in addressing climate change is MORE THAN 65%? Given: a= 0.05 level 1. List your oH and aH: (symbols and words) 2. State and Check the conditions for the test: 3. Use the information in question: Identify the hypotheses being tested: Find your SE and test statistic by hand: 4. Use the information in question: State your conclusion given 05.0 level, in a complete sentence, in the context of the problem. 5. Use the information in question. Find the 95% confidence interval by hand using: Given z*=1.96
Maple syrup is a non-negligible nutritional source of manganese. It is made from the sap of two species of maple: the sugar maple and the black maple. To see if there is a significant difference between the manganese content of these two species of maple, we measured the manganese content (in mg per 100g syrup) for a sample of sugar maples and a sample of black maples. The data is summarized by the Minitab output below: Two-sample T for Sugar Maple Black Maple group N Mean St Dev SE Mean Sugar Maple 20 Black Maple 12 3.55 0.29 Find: (i) a point estimate for ₁-2, where ₁ and 2 are the average manganese contents of the sugar maple, respectively the black maple; (ii) the standard error of X₁ - X₂. A) (i) -0.07; (ii) 0.101 C) (i) -0.26; (ii) 0.097 E) (i) -0.07; (ii) 0.035 3.29 0.22 0.049 0.084 B) (i) -0.26; (ii) 0.188 D) (i) -0.26; (ii) 0.101
When trying to determine how many samples are needed to perform an experiment, the desired accuracy of the results are often a determining factor. Dr. Smith has designed a new scanner capable of determining blood bilirubin levels using a cell phone. Because this is a diagnostic device, Dr. Smith is concerned not just about having small standard errors, but also having good estimates for population percentiles. If he needs to determine the 95th percentile to an accuracy of 5%, what is the number of samples needed to ensure that the percentile as determined from his data (using a t distribution) is within 5% of the percentile as calculated as if the standard deviation was taken from the entire population (using a z distribution)?
A small pilot study is conducted to investigate the effect of a nutritional supplement on total body weight. Six participants agree to take the nutritional supplement. To assess its effect on body weight, weights are measured before starting the supplementation and then after 6 weeks. The data are shown below. Is there a significant increase in body weight following supplementation? Run the test at a 5% level of significance. Demonstrate the five steps for hypothesis testing and explain your results. Subject Initial Weight Weight after 6 Weeks 1 155 157 2 142 145 3 176 180 4 180 175 5 210 209 6 125 126
A new screening test for Lyme disease is developed for use in the general population. The sensitivity and specificity of the new test are 60% and 70%, respectively. Five hundred people are screened at a clinic during the first year the new test is implemented. Assume the true prevalence of Lyme disease among clinic attendees is 10%. Calculate the predictive value of a positive test.
while estimates vary, one website indicated that approximately 44% of US citizens have type O blood. A statistics class tested this claim by having students identify their blood types. In a sample of 64 students, 26 indicated their blood type to be type O. At a=.01, test that the percentage of US citizens with type O blood is less than 44%. The hypotheses for this situation are:
Genetic drugs are lower cost substitutes for brand-name drugs. Before a genetic drug can be sold in the United States, it must be tested found to perform equivalently to the brand-name product. The U.S. Food and Drug Administration is now supervising the testing of new genetic antifungal ointment. The Brand-name ointment is known to deliver a mean of 3.5 micrograms of active ingredient to each square centimeter of skin. As part of the testing, seven subjects apply the ointment. Six hours later, the amount of drugs that has been absorbed into the skin measured. The amounts, in micrograms, are 2.6, 3.2, 2.1, 3.0, 3.1, 2.9, 3.7 How strong is the evidence that the mean amount absorbed differs from 3.5 micrograms? Test by using a confidence interval with ?=0.05α=0.05. Show Step1-Step3. Round critical value to nearest hundredth. (e.g. 0.1256 would be entered as 0.13) Round confidence interval to nearest thousandth. (e.g. 0.12456 would be entered as 0.125)
The recidivism rate for convicted sex offenders is 12%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 322 convicted sex offenders who were also drug addicts, 48 of them became repeat offenders. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for a population proportion V b. The null and alternative hypotheses would be: Ho: ? v Select an answer (please enter a decimal) H1: ? v Select an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? V a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population proportion is not significantly different from 12% at a = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of…
What are the missing values for Between and Within treatment, in terms of DF, MS and F?

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