Water (5.0 L/min) is flowing in a tube "D = 3 cm, L= 5 m" and is to be neated from 15°C to 64.0°C by applying a uniform heat flux on the outer surface of the tube by electric resistance heater. What is the convective heat transfer coefficient (W/m .K)? 0.8 If turbulent flow use Dituss-Boetler relation Nu= 0.023 Re Pr. Properties : p= 992.1 kg/m , C,= 4179 J/kg.°C, k = 0.631 W/m°C, Pr = 4.32, v = 0.658E-6 m/s

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Water (5.0 L/min) is flowing in a tube "D = 3 cm, L= 5 m" and is to be neated from 15°C
to 64.0°C by applying a uniform heat flux on the outer surface of the tube by electric
resistance heater. What is the convective heat transfer coefficient (W/m .K)?
%3D
0.8
If turbulent flow use Dituss-Boetler relation Nu= 0.023 Re
Pr.
3
Properties : p= 992.1 kg/m , C,= 4179 J/kg. °C, k = 0.631 WM°C, Pr = 4.32, v = 0.658E-6
m /s
Select one
Transcribed Image Text:Water (5.0 L/min) is flowing in a tube "D = 3 cm, L= 5 m" and is to be neated from 15°C to 64.0°C by applying a uniform heat flux on the outer surface of the tube by electric resistance heater. What is the convective heat transfer coefficient (W/m .K)? %3D 0.8 If turbulent flow use Dituss-Boetler relation Nu= 0.023 Re Pr. 3 Properties : p= 992.1 kg/m , C,= 4179 J/kg. °C, k = 0.631 WM°C, Pr = 4.32, v = 0.658E-6 m /s Select one
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