v=Pa/m (c) Determine the total energy released during the decay of 1 mole of bismuth 212: (5.98 x 10¹¹J)
v=Pa/m (c) Determine the total energy released during the decay of 1 mole of bismuth 212: (5.98 x 10¹¹J)
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how would you do part c? this is a non graded practice worksheet
Transcribed Image Text:1. A bismuth isotope decays into thallium by emitting an alpha particle according
to the following equation: +
217
mass
Atomic #83 only protons.
Bi → TI + He
(a) Determine the atomic number Z and the mass number A of the thallium nuclei produced and enter your
answers in the spaces provided below.
Z = 81
A
213
The mass of the alpha particle is 6.64 x 10-27 kg. Its measured kinetic energy is 6.09 MeV and its speed is much
less than the speed of light.
46.09 ebev
9.744e-13 J
(a) Determine the momentum of the alpha particle. (1.14 x 10-¹9 kg m/s)
K=//mv²
9.744e-13-1 (6.64x10-27)√²
P=mv
v=1.713e7 m/s.
articles
(b) Determine the kinetic energy of the recoiling thallium nucleus. (1.93 x 10-¹4J)
LSS == 213 0 = 1.66 X10-27 (213) = 353,58e-27 kg
P--Pa
mass
V=1.1386-199s from
353.58e-27
my-la
0
PILYS
dicas
K = 1/2mv ² ====₂(
-1.84е-145
ST
(c) Determine the total energy released during the decay of 1 mole of bismuth 212: (5.98 x 10¹¹J)
v=Pa/m
P=6164x10-27 (1.713e7)
P =1.138e-19 kgm/s/
=3.224 15m/s
dont on the metal
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