8. In a mass spectrometer a charged particle is accelerated to a velocity v = 5.9 107 m/s by an electric field and allowed to enter a magnetic field B, where it is deflected in a semi-circular path of radius R = 10 cm. The magnetic field is uniform of magnitude B = 16 T and oriented out of the page. What is the sign of the charge on the particle? b. What is the acceleration of the particle in the magnetic field? C. What is the ratio between the charge and mass of the particle q/m? evebliot nova Le M d. What is the direction of the accelerating electric field? e. What is the accelerating voltage of the electric field? Ositive be the FM is downwards m q B 00

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how do you do part d? this is a non graded practice worksheet
8.
In a mass spectrometer a charged particle is accelerated to a velocity v = 5.9 107 m/s by an electric field and
allowed to enter a magnetic field B, where it is deflected in a semi-circular path of radius R = 10 cm. The
magnetic field is uniform of magnitude B = 16 T and oriented out of the page.
a. What is the sign of the charge on the particle?
ai evollot moovi List
b. What is the acceleration of the particle in the magnetic field?
C. What is the ratio between the charge and mass of the particle q/m?
What is the direction of the accelerating electric field?
d.
e.
What is the accelerating voltage of the electric field?
a) positive be the fu is downwards
(b) a=v²
Y
c = 3.481 e 16 m/s²,
c)
:) magnetic force is acting as
the centripetal force
q (VB)=my²
2
c = (5.9x107)² ni nobels silt to nor step to shatingem od 92m1915) ins
R
9/m = Y/AB
q
m
5.9x107
(.01)(16)
-3.68 x 10
m
7
M
ava
dup
Transcribed Image Text:8. In a mass spectrometer a charged particle is accelerated to a velocity v = 5.9 107 m/s by an electric field and allowed to enter a magnetic field B, where it is deflected in a semi-circular path of radius R = 10 cm. The magnetic field is uniform of magnitude B = 16 T and oriented out of the page. a. What is the sign of the charge on the particle? ai evollot moovi List b. What is the acceleration of the particle in the magnetic field? C. What is the ratio between the charge and mass of the particle q/m? What is the direction of the accelerating electric field? d. e. What is the accelerating voltage of the electric field? a) positive be the fu is downwards (b) a=v² Y c = 3.481 e 16 m/s², c) :) magnetic force is acting as the centripetal force q (VB)=my² 2 c = (5.9x107)² ni nobels silt to nor step to shatingem od 92m1915) ins R 9/m = Y/AB q m 5.9x107 (.01)(16) -3.68 x 10 m 7 M ava dup
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