(viscosity: v = 1 × 10-6 m² /s, SG = 0.9) flows from the upper voir at a rate of 0.028 m³/s in the 15 cm (diameter) smooth pipe is the elevation of the oil surface in the upper reservoir. Elevation = ? 60 m //=2< 7m 130 m (2) Ele
(viscosity: v = 1 × 10-6 m² /s, SG = 0.9) flows from the upper voir at a rate of 0.028 m³/s in the 15 cm (diameter) smooth pipe is the elevation of the oil surface in the upper reservoir. Elevation = ? 60 m //=2< 7m 130 m (2) Ele
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Example 8 (Page 271):
If oil (viscosity: \( v = 1 \times 10^{-6} \, \text{m}^2/\text{s} \), SG = 0.9) flows from the upper to the lower reservoir at a rate of 0.028 m³/s in the 15 cm (diameter) smooth pipe.
What is the elevation of the oil surface in the upper reservoir?
Formula:
\[
h_L = \sum_{\text{pipe}} f \frac{L}{D} \frac{V^2}{2g} + \sum_{\text{component}} K \frac{V^2}{2g}
\]
Diagram Explanation:
1. Upper Reservoir: The elevation is marked as unknown. Oil flows through a 60 m straight pipe segment.
2. The pipe has a bend with a radius to diameter ratio \( r/D = 2 \).
3. After the bend, the pipe descends 7 m and continues horizontally for 130 m into the lower reservoir.
4. Lower Reservoir: This has a fixed elevation at 130 m.
The diagram illustrates the flow of oil from the upper to the lower reservoir through a system of pipes, indicating the distance and direction of each segment, along with the elevation changes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F89ff9c08-d82f-4c45-91c3-3510df7b72b7%2F60f0cc94-4ccb-4a75-9d7e-3a96e2d1c2fd%2Fqvy1nml_processed.png&w=3840&q=75)
Transcribed Image Text:Example 8 (Page 271):
If oil (viscosity: \( v = 1 \times 10^{-6} \, \text{m}^2/\text{s} \), SG = 0.9) flows from the upper to the lower reservoir at a rate of 0.028 m³/s in the 15 cm (diameter) smooth pipe.
What is the elevation of the oil surface in the upper reservoir?
Formula:
\[
h_L = \sum_{\text{pipe}} f \frac{L}{D} \frac{V^2}{2g} + \sum_{\text{component}} K \frac{V^2}{2g}
\]
Diagram Explanation:
1. Upper Reservoir: The elevation is marked as unknown. Oil flows through a 60 m straight pipe segment.
2. The pipe has a bend with a radius to diameter ratio \( r/D = 2 \).
3. After the bend, the pipe descends 7 m and continues horizontally for 130 m into the lower reservoir.
4. Lower Reservoir: This has a fixed elevation at 130 m.
The diagram illustrates the flow of oil from the upper to the lower reservoir through a system of pipes, indicating the distance and direction of each segment, along with the elevation changes.
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