Example 8 (Page 271):If oil (viscosity: \( v = 1 \times 10^{-6} \, \text{m}^2/\text{s} \), SG = 0.9) flows from the upper to the lower reservoir at a rate of 0.028 m³/s in the 15 cm (diameter) smooth pipe.What is the elevation of the oil surface in the upper reservoir?Formula:\[ h_L = \sum_{\text{pipe}} f \frac{L}{D} \frac{V^2}{2g} + \sum_{\text{component}} K \frac{V^2}{2g} \]Diagram Explanation:1. Upper Reservoir: The elevation is marked as unknown. Oil flows through a 60 m straight pipe segment.2. The pipe has a bend with a radius to diameter ratio \( r/D = 2 \).3. After the bend, the pipe descends 7 m and continues horizontally for 130 m into the lower reservoir.4. Lower Reservoir: This has a fixed elevation at 130 m.The diagram illustrates the flow of oil from the upper to the lower reservoir through a system of pipes, indicating the distance and direction of each segment, along with the elevation changes.

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(viscosity: v = 1 × 10-6 m² /s, SG = 0.9) flows from the upper voir at a rate of 0.028 m³/s in the 15 cm (diameter) smooth pipe is the elevation of the oil surface in the upper reservoir. Elevation = ? 60 m //=2< 7m 130 m (2) Ele

(viscosity: v = 1 × 10-6 m² /s, SG = 0.9) flows from the upper voir at a rate of 0.028 m³/s in the 15 cm (diameter) smooth pipe is the elevation of the oil surface in the upper reservoir. Elevation = ? 60 m //=2< 7m 130 m (2) Ele

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Example 8 (Page 271):

If oil (viscosity: \( v = 1 \times 10^{-6} \, \text{m}^2/\text{s} \), SG = 0.9) flows from the upper to the lower reservoir at a rate of 0.028 m³/s in the 15 cm (diameter) smooth pipe.

What is the elevation of the oil surface in the upper reservoir?

Formula:
\[
h_L = \sum_{\text{pipe}} f \frac{L}{D} \frac{V^2}{2g} + \sum_{\text{component}} K \frac{V^2}{2g}
\]

Diagram Explanation:

1. Upper Reservoir: The elevation is marked as unknown. Oil flows through a 60 m straight pipe segment.
2. The pipe has a bend with a radius to diameter ratio \( r/D = 2 \).
3. After the bend, the pipe descends 7 m and continues horizontally for 130 m into the lower reservoir.
4. Lower Reservoir: This has a fixed elevation at 130 m.

The diagram illustrates the flow of oil from the upper to the lower reservoir through a system of pipes, indicating the distance and direction of each segment, along with the elevation changes.

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